Chemistry
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Concept explainers

Carbohydrates
Carbohydrates are the organic compounds that are obtained in foods and living matters in the shape of sugars, cellulose, and starch. The general formula of carbohydrates is Cn(H2O)2. The ratio of H and O present in carbohydrates is identical to water.
Starch
Starch is a polysaccharide carbohydrate that belongs to the category of polysaccharide carbohydrates.
Mutarotation
The rotation of a particular structure of the chiral compound because of the epimerization is called mutarotation. It is the repercussion of the ring chain tautomerism. In terms of glucose, this can be defined as the modification in the equilibrium of th…
L Sugar
A chemical compound that is represented with a molecular formula C6H12O6 is called L-(-) sugar. At the carbon’s 5th position, the hydroxyl group is placed to the compound’s left and therefore the sugar is represented as L(-)-sugar. It is capable of rotat…
Question
What is the correct answer and why?
**Title: Identifying Meso Compounds** **Question:** Which of the following is properly classified as a *meso* compound? **Choices:** - **Option A:** - Structure: Two carbon atoms, each bonded to a methyl group (CH₃), a hydroxyl group (OH), and a hydrogen atom (H). - Diagram: Stereo center symmetry is suggested. - **Option B:** - Structure: Two carbon atoms, each bonded to a hydrogen atom and two hydroxyl groups. - Diagram: No symmetry due to the positioning of hydroxyl groups. - **Option C:** - Structure: Two carbon atoms, each bonded to an ethyl group (C₂H₅), a hydroxyl group (OH), and a hydrogen atom. - Diagram: Shows symmetry across central carbon atoms. - **Option D:** - Structure: Two carbon atoms, one bonded to an ethyl group (C₂H₅) and the other bonded to a methyl group (CH₃), each with a hydroxyl group (OH). - Diagram: Asymmetric arrangement. **Answer Choices:** - ○ A - ○ B - ○ C - ○ D **Explanation:** When identifying meso compounds, look for criteria that include internal plane symmetry. The compound must have multiple stereocenters and an internal mirror plane, effectively making it optically inactive despite having chiral centers. In this question, Option C shows the necessary internal symmetry to be classified as a meso compound.
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Transcribed Image Text:**Title: Identifying Meso Compounds** **Question:** Which of the following is properly classified as a *meso* compound? **Choices:** - **Option A:** - Structure: Two carbon atoms, each bonded to a methyl group (CH₃), a hydroxyl group (OH), and a hydrogen atom (H). - Diagram: Stereo center symmetry is suggested. - **Option B:** - Structure: Two carbon atoms, each bonded to a hydrogen atom and two hydroxyl groups. - Diagram: No symmetry due to the positioning of hydroxyl groups. - **Option C:** - Structure: Two carbon atoms, each bonded to an ethyl group (C₂H₅), a hydroxyl group (OH), and a hydrogen atom. - Diagram: Shows symmetry across central carbon atoms. - **Option D:** - Structure: Two carbon atoms, one bonded to an ethyl group (C₂H₅) and the other bonded to a methyl group (CH₃), each with a hydroxyl group (OH). - Diagram: Asymmetric arrangement. **Answer Choices:** - ○ A - ○ B - ○ C - ○ D **Explanation:** When identifying meso compounds, look for criteria that include internal plane symmetry. The compound must have multiple stereocenters and an internal mirror plane, effectively making it optically inactive despite having chiral centers. In this question, Option C shows the necessary internal symmetry to be classified as a meso compound.
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