Which of the following is NOT true for conducting a hypothesis test forindependence between the row variable and column variable in a contingency table?O Small values of the chi squared test statistic reflect significant differencesbetween observed and expected frequencies.O The null hypothesis is that the row and column variables are independent ofeach other.O Tests of independence with a contingency table are always right-tailed.O The number of degrees of freedom is (r-1)(c-1), where r is the number of rowsand c is the number of columns.

Introduction: It is required to identify the statement that is not true in relation to a chi-squared…

Answered: Which of the following is NOT true for…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Test the claim that the proportion of people who own cats is smaller than 10% at the 0.025 significance level. The null and alternative hypothesis would be: Ho p ≤ 0.1 Ho:μ = 0.1 Ho:p 0.1 H₁:p> 0.1 H₁:μ 0.1 H₁:p ‡ 0.1 O The test is: = left-tailed two-tailed right-tailed Based on this we: Based on a sample of 600 people, 5% owned cats The p-value is: Ho≥ 0.1 Ho: ≤0.1 Ho:p> 0.1 H₁:μ 0.1 H₁:p < 0.1 O O Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals)
Test the claim that the mean GPA of night students is larger than 2.6 at the 0.01 significance level. The null and alternative hypothesis would be: Ho:p > 0.65 Ho:p 2.6 H1:p 0.65 H1:p+ 0.65 H1:µ > 2.6 H1:µ + 2.6 H:µ < 2.6 %3D The test is: two-tailed right-tailed left-tailed Based on a sample of 65 people, the sample mean GPA was 2.63 with a standard deviation of 0.07 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Fail to reject the null hypothesis O Reject the null hypothesis
Test the claim that the mean GPA of night students is larger than 2.8 at the .10 significance level. The null and alternative hypothesis would be: Ho: p=0.7 Ho: p = 0.7 Ho:μ = 2.8 Ho: H₁:p> 0.7 H₁:p 2.8 H₁: The test is: left-tailed two-tailed right-tailed o The test statistic is: 2.8 Ho:p = 0.7 Ho:μ = 2.8 0 <2.8 H₁:p 0.7 H₁: 2.8 Based on a sample of 40 people, the sample mean GPA was 2.83 with a standard deviation of 0.02 (to 2 decimals) The critical value is: = (to 2 decimals)
Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.025 significance level. The null and alternative hypothesis would be: Ho: HN S HD Ho:pN 2 PD Ho:PN = PD Ho:UN = HD Ho: PN HD H:PN PD H1: µN Next Question hp
Test the claim that the mean GPA of night students is larger than 2.4 at the 0.025 significance level. The null and alternative hypothesis would be: Ho: µ = — 2.4 Но:р 2.4 Н: + 2.4 H:p> 0.6 H:д> 2.4 Hi:p #0.6 Hi:p < 0.6 Н:р < 2.4 The test is: left-tailed two-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.41 with a standard deviation of 0.03 The test statistic is: (to 2 decimals) The p-value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis
Q1 Probability and Statistics
Test the claim that the mean GPA of night students is larger than 2 at the 0.005 significance level. The null and alternative hypothesis would be: Но:р 2 Нo:д 0.5 Но:и — 2 Нi:р> 0.5 H:n 2 Hi:p#0.5 Hі:р<0.5 Hі:р +2 The test is: two-tailed left-tailed right-tailed Based on a sample of 65 people, the sample mean GPA was 2.02 with a standard deviation of 0.08 The p-value is: (to 2 decimals) Based on this we: Fail to reject the null hypothesis O Reject the null hypothesis
The test statistic in a left-tailed test is z=−0.59. Determine the P-value and decide whether, at the 10% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. The P-value is ___________ (Round to four decimal places as needed.) This P-value ________________ (provides, does not provide) sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis because it is_____________(greater than, less than) the significance level.
ble shows the Myers-Briggs personality preferences for a random sample of 406 people in the listed professions. E refers to extroverted and I refers to introverted. Personality Type Occupation Clergy (all denominations) E Row Total 65 42 107 M.D. 70 92 162 Lawyer Column Total 54 83 137 189 217 406 A USE SALT Use the chi-square test to determine if the listed occupations and personality preferences are independent at the 0.05 level of significance. (a) What is the level of significance? State the null and alternate hypotheses. O Ho: Myers-Briggs preference and profession are not independent H: Myers-Briggs preference and profession are independent. O Ho: Myers-Briggs preference and profession are independent H: Myers-Briggs preference and profession are independent. O H: Myers-Briggs preference and profession are independent H: Myers-Briggs preference and profession are not independent. O Ho: Myers-Briggs preference and profession are not independent H,: Myers-Briggs preference and…
You are interested in investigating whether gender and major are associated at your college. The table below shows the results of a survey. Math/Science Arts/Humanities Business/Econ. Other Men 76 109 73 49 Women 82 96 93 34 What can be concluded at the αα = 0.01 significance level? What is the correct statistical test to use? Independence Homogeneity Goodness-of-Fit Paired t-test What are the null and alternative hypotheses?H0:H0: The distribution of college major is the same for each gender. College major and gender are independent. College major and gender are dependent. The distribution of college major is not the same for each gender. H1:H1: College major and gender are independent. The distribution of college major is not the same for each gender. College major and gender are dependent. The distribution of college major is the same for each gender. The test-statistic for this data = (Please show your answer to three decimal places.) The p-value for…
A psychologist specializing counseling claims that, among all married couples, the proportion p for whom her communication program can prevent divorce 79% . In a random sample of 240 married couples who completed her program, 174 of them stayed together. Based on this sample, can we reject the psychologist's claim at the 0.1 level of significance The null hypothesis: H0: ___ The alternative hypothesis: H1: ___ The type of test statistic: (Choose one) ___ The value of the test statistic: (Round to at least three decimal places.) ______ The p-value: (Round to at least three decimal places.) _____ Can we reject psychologist’s claim that the Proportion of married couples for whom her Program can prevent divorce is a least 79%? Yes ____ or NO____
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