Which of the following is NOT a unit of concentration?     All of these options are units of concentration.     mM     Moles/Liter     Molar   You gathered your data from Lab , and found the following values: Total Activity of lysozyme in HEW: 14 units Total Activity of lysozyme in carb 1: 21 units Total amount of protein in HEW: 70 mg Total amount of protein in Carb 1: 15 mg Calculate the extent of purification of lysozyme in Carb 1. A   7 fold B   150% C   15 fold D   70%

What is the function of sodium dodecyl sulfate (SDS) in SDS-PAGE? stabilizes the gel matrix, improving resolution during electrophoresis SDS solubilizes proteins to give them uniformly negative charges, so the separation is based purely on size. SDS raises the pH of the gel, separating multiunit proteins into individual subunits. SDS solubilizes proteins to give them uniformly positive charges, so separation is based purely on pH.

This is a visible spectra between 390-590 nm obtained during the protein separation process of haemoglobin and cytochrome c using CM Sephadex chromatography. I'd like the results shown on the image interpreted. Look for characteristic peaks or patterns that correspond to the absorption properties of these proteins in the visible range.

You are given an equimolar (0.10 mM) mixture of Ubiquitin protein that is free/pure of any other macromolecules (e.g. nucleic acids) in a pH 7.0 phosphate buffer How can you purify Ubiquitin? Propose a 2-step minimum plan to purify their protein. Basic rules:  Affinity chromatography (e.g. His Tag purification) is not an allowed step because these proteins are in their native state (i.e. – do not have a polyhistidine tag). Also, you are not allowed to rely solely on the color of certain proteins (e.g. cytochrome C and GFP) in your characterization/proposal. You are allowed to buffer exchange (i.e. – switch buffers) but try to keep your pH’s in a reasonable range (5.5 – 8.5) or you risk denaturing your protein! Assume you can only separate proteins under 50.0 kDa with a 5.0 kDa difference using SEC. Otherwise, assume proteins greater than 50.0 kDa are unable to be separated. Assume proteins with the same charge (positive or negative) are not easily separated using IEC. Assume all…

Does this calculation look correct? My goal isto have a target mass of 10 µg of my protein with a total volume of 30 µl. Protein was measured and found to have a concentration of at 308.35 µg/ml Recall, mass = concentration * volume 10 µg = 308.35 µg/ml * V V = 0.01 mg/ 0.30835 mg/mL = 0.032430679 mL = 32.43067942 µL Note: cannot measure this amount; two dilutions required. Dilute by 1/40: measure 2.5 µl of protein at 0.30835 µg/µl and add it to 97.5 diluent to prepare a solution of protein at 7.71 mg/ml. This diluted sample will be used further. Mass = concentration * volume 10 µg = 7.71 mg/ml * V V = 0.01 mg/ 7.71 mg/ml = 1.3 µL Therefore, will measure 1.3 µl of protein at 7.71 mg/ml and add it to 28.7 µl of diluent.

A purified protein sample was used in a reaction, resulting in an activity of 696.7 nmol min-1. The reaction volume was 145.0 µL and the final volume before loading the plate was 1,050 µL. The total reaction time was 4.25 min. The amount of protein used in the reaction was 4.270 µg. Calculate the specific activity of the sample (in nmol min-1 µg-1).

Please answer the question below and show all your work. You are given a pure protein sample to characterize and provided the following information: Its molar extinction coefficient, ε280, is 0.25 liters micromole^-1 cm^-1 Using a 0.5 cm pathlength cell, you measure the absorbance at 280 nm of a 20- fold dilution of your pure protein in solution (by this, we mean that 50 ul of the protein sample was diluted to a final volume of 1 ml) and find A280 = 0.40. What is the original concentration of the protein before dilution?

100ml of LB media with 25 μg/ml of Amp and 100 μg/ml of Kan final concentration. You have 100ml of LB provided and Amp and Kan stocks at 100 mg/ml and 50 mg/ml provided. Determine how much of each antibiotic stock solution you need to add to 100ml of LB to reach desired antibiotic concentration.

Make a table with a scale of absorbance and the concentration of protein in Chromatin sample from the following data for excel graph Absorbance=660nm following data are of tubes with concern  A =0 B=0.036 C=0.011 D=0.001 E=0.027 F=0.020 G=0.032 H1=0.176 H2=0.183 I1=0.150 I2=0.171 also plot the graph??

You perform electrophoresis of 3 proteins, Hemoglobin (pl: 6.8), DNA Polymerase (pl: 5.2) and Porcine pepsin (pl: 1.0) in a Tris-Glycine buffer (pH 5.2). (pl = Isoelectric point). Select which of the following is true. O All proteins will migrate at the same rate O All proteins will migrate at the same direction Porcine pepsin will migrate toward the electrode Porcine pepsin will not migrate and stay in the well