
Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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![Which of the following best describes [HSO4] in a 0.1 M solution of H₂SO4?
= OM
= 0.1 M
a little more than 0.1 M
a little less than 0.1 M](https://content.bartleby.com/qna-images/question/0b4eade4-54e6-4adb-8628-0396c54f5e3a/7b8bb8e2-61fa-4f65-a936-ac941a7a5dd6/1m52ts_thumbnail.jpeg)
Transcribed Image Text:Which of the following best describes [HSO4] in a 0.1 M solution of H₂SO4?
= OM
= 0.1 M
a little more than 0.1 M
a little less than 0.1 M
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- Predominant form Classification (acid, base, salt, molecular, metal, etc.) Strong Electrolyte? Formula Solubility in substance exists as in an Water aqueous system NaNO; Salt significant yes Na*(aq) + NO; (aq) CH;OH Molecular significant CH;OH(aq) no HCI Acıd significant Yes Ca3(PO4)2 trace amounts Fe(C,H,O,); significant NaOH significant Mg(OH), trace amounts HNO, significant H,O N/A CO2 some what K,Cr,O, significant C12H2O11 significant Ca(OH)2 significant PCI, significant Li,SO4 significant HBRO significant HCIO4 significant BaSO4 trace amounts AgNO; significant trace amounts AgCl insoluble Ag HI significant RÜHCO; significantarrow_forwardThe acidity of a solution is measured by its pH. If (T*] represents the concentration of hydrogen ions (in moles/liter) in the solution, the pH is defined by pH = – log Ht || Suppose a solution has pH = 1.98. (a) Rewrite the logarithmic form of the equation into exponential form. indicates two way equivalence) Click for List - ] – log H+ pH O Click for List Click for List (b) Find Ht, the approximate concentration of hydrogen ions. (Select one) O [H*]= 0.2967 moles/liter [H']~0.5051 moles/liter O [H*]= 0.01047 moles/liter O [H*]~ -0.2967 moles/liter O [H*]=0.03177 moles/liter [H*]= -95.4993 moles/liter O [H*]=3.3708 moles/literarrow_forwardReaction will occur Reaction will not occur Anower Bank Ag(a) Co(NO,),(on) NO.1,(0) Za() Sa(NO,),(a) Ni(s) Za(NO).(aq) Co(s) CaNO,),(a)arrow_forward
- . So, we need 5.00 mmol of base (titrant) to be delivered to the analyte. Since we know the molarity of the base and moles of base, we just need to solve for the volume of base (titrant) to be added. molpase Mpase = Voladded Molarity base =. 0.150 (M) Moles of base = _5.00 (mmol) Volume of base needed to reach equivalence point _ (mL)arrow_forwardA chemical reaction doesn't necessarily involve electrons. °F Mostly sunny F1 O ! 1 Q A N True F2 2 W S F3 Alt -8+ X #M 3 E F4 D ta + $ 4 C F5 R 2 F % 5 F6 V T G F7 6 Y B F8 & 7 H U N F9 *00 8 J F10 ( 9 M O False K GO F11 O @ ) 0 < F12 L P Altarrow_forward4 help use sig figsarrow_forward
- Solutions for (a),(b) and (c) please.arrow_forwardIn the following reaction in aqueous solution, the acid reactant is base reactant is HONH2 (aq) + HCO3(aq) = CO32- (aq) + HONH3+ (aq) HONH2; HCO3 HONH3; HONH2 HCO3; HONH2 HCO3; CO3²- HONH2; CO32- and thearrow_forward5) If all the NaHCO3 in bag 2 reacted, calculate the number of moles of gas produced? tates) E Focusarrow_forward
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