Which feature (antibiotic target) of bacteria seems to be the most resistant to antibiotics? Why might that be? ABResistant Strains (%)Resistant Strains (%)100 305 Ribosome90 505 Ribosome80 Folate Pathway70 DNA/RNA SynthesisCell Wall SynthesisCell Membrane60504030200Apramycin2010NeomycinStreptomycinGentamicin100 1305 Ribosome90 - 50S Ribosome80 Folate Pathway70 DNA/RNA Synthesis60 Cell Wall Synthesis504030TetracyclineTigecyclineMinocyclineClindamycinApramycinGentamicinNeomycinTetracyclineStreptomycinMinocyclineSynercidTigecyclineErythromycinChloramphenicolTelithromycinClindamycinChloramphenicolLinezolidTrimethoprimSulfamethoxazoleAntibiotic (20 ug/ml)CiprofloxacinRifampicinErythromycinTelithromycinCiprofloxacinTrimethoprimSulfamethoxazoleAntibiotic (20 µg/ml)NovobiocinRifampicinCefotaximeVancomycinMeropenemCefotaximeGram +veMeropenemaysajeudayCephalexinFosfomycinFosfomycin«{{{{{cruAmpicillinGram -vePiperacillinDaptomycinPiperacillin

Antibiotics are the substances or anti microbial substances that are produced by one microbe and…

Answered: Which feature (antibiotic target) of…

Science

Biology

Which feature (antibiotic target) of bacteria seems to be the most resistant to antibiotics? Why might that

Biology 2e

2nd Edition

ISBN:9781947172517

Author:Matthew Douglas, Jung Choi, Mary Ann Clark

Publisher:Matthew Douglas, Jung Choi, Mary Ann Clark

Chapter22: Prokaryotes: Bacteria And Archaea

Section: Chapter Questions

Problem 23RQ: Which of these statements is true? An antibiotic is any substance produced by a organism that is...

See similar textbooks

Similar questions

Practice Case study p. 224 part: Tuberculosis (TB) in indigenous populations. Lily was a recent science graduate of the University of Alberta and was 11 months into her 12 - month Master of Science in Global Health degree, at Dalhousie University. This relatively new program was created to provide the multidisciplinary training required of scientists working to meet the complex challenges of global public health issues. The University had partnered with the National Collaborating Centre for Indigenous Health (NCCIH) and that was why Lily now found herself doing her Global Health Field Practicum in the Northern Territories, working on a study of drug resistant TB infections among Innuit communities. The different communities included in her research were close to 7000 individuals, with multiple diagnosed cases of TB. And while she was grateful that drug-resistant TB in Canada remained below the global average (Public Health Agency of Canada, 2019), she was cognizant of the possibility…
Practice Case study p. 224 part: Tuberculosis (TB) in indigenous populations. Lily was a recent science graduate of the University of Alberta and was 11 months into her 12 - month Master of Science in Global Health degree, at Dalhousie University. This relatively new program was created to provide the multidisciplinary training required of scientists working to meet the complex challenges of global public health issues. The University had partnered with the National Collaborating Centre for Indigenous Health (NCCIH) and that was why Lily now found herself doing her Global Health Field Practicum in the Northern Territories, working on a study of drug resistant TB infections among Innuit communities. The different communities included in her research were close to 7000 individuals, with multiple diagnosed cases of TB. And while she was grateful that drug-resistant TB in Canada remained below the global average (Public Health Agency of Canada, 2019), she was cognizant of the possibility…
The most selectively toxic antibacterial agents are those that interfere with bacterial cell wall synthesis. This is because ________. Group of answer choices bacterial cell wall synthesis is easily inhibited whereas eukaryotic cell wall synthesis is more resistant to the actions of the drugs bacterial cell walls have a unique structure not found in eukaryotic host cells eukaryotic cells do not take up the drugs eukaryotic cells inactivate the drugs before they can do any damage
Arial BIUA 11 + .. | I 1 I 3 I 4 i.) Fill in the table for each of the E. coli: (0) = No Activity (+) = Basal Activity and (+++) = High Activity E. coli chromosome F' Plasmid B-gal activity? Permease activity? When When When When Glucose is Lactose is Glucose is Lactose is present present present present a.) I+ P+ O+ Z+ Y+ Inone +++ +++ b.) I^[S] P+ O+ Z+ Y+ none c.) I+ P+ O^[c] Z+ Y+ none d.) I+ P+ O- Z- Y+ none e.) I+ P+ O+ Z+ Y+ I^[S] P+ O+ Z+ Y+ f.) I^[S] P+ O+ Z- Y+ I+ P+ O^[c] Z+ Y- g.) I^[TB] P+ O+ Z+ Y 1+ P+ O^[c] Z- Y+ h.) I+ P+ O^[c] Z+ Y- I+ P+ O+ Z** Y+ i.) I^[TB] P+ O^[c] Z+ Y- 1+ P+ O+ Z- Y+ Z** is a polar mutation ii. ) If the lac operon in 'a' carried a mutation in the CAP binding site that rendered it nonfunctional, how would that affect the level of ß-galactosidase protein activity with and without lactose present, why? MacBook Air 000
Microbiology (Match the phrases from column (A) with phrases in column (B Bacterial Bacterial chromosome Donor Peptidoglyca B-lactam drug Codon Lysosomes Plasma Methionin Methylatio cell growth membrane AUG Haploid Restriction enzymes AGC Cytoskeleto Auto digestion Transpeptid ases PBPS Housekeepi ng genes Sex pili Anima Chromophor SASP Axial Asbestos Elimination Proteins peptidoglyca carcas degradation filament H202 Dormant ses Endospore Exosporium Disinfection Fumigation Filtration Cortex Sporulation Germinatio Dye Incineration
Which of these statements is true? An antibiotic is any substance produced by a organism that is antagonistic to the growth of prokaryotes An antibiotic is any substance produced by a prokaryote that is antagonistic to the growth of other viruses An antibiotic is any substance produced by a prokaryote that is antagonistic to the growth of eukaryotic cells An antibiotic is any substance produced by a prokaryote that prevents growth of the same prokaryote.
Row C D. B B. one: A C O phage with radiolabelled protein coat phage with radiolabelled DNA 100 10. phage infects The experiment shown above was designed by bacterium phage infects bacterium EXPERIMENT 1 phage shell is removed EXPERIMENT 2 요 Hershey & Hershey & Chase Meselson & Stahl Meselson & Stahl 8 phage shell is removed 28 no radioactivity in cells ii 48 radioactivity in cells LL and proved that ii DNA replication is semiconservative DNA is the hereditary material DNA replication is semiconservative DNA is the hereditary material (select the row that correctly completes the statement)
anline State- estid%3D1740&strandid%3D&element3D&difficulty=Dassessment&assignment_id%3D42985127&load_test=1&teacherPreview=#test Save Subm gp120 Docking Glycoprotein Lipid Membrane RNA gp41 Transmembrane Glycoprotein Сapsid Matrix Reverse Transcriptase Viruses, although not considered to be alive, attack host cells and cause disease. The attack of a host cell is necessary for the virus to survive for all of the reasons listed EXCEPT one. That is they cannot synthesize proteins becayse they lack ribosomes and must use the ribosomes of their host cells to translate viral messenger RNA into new Eliminate proteins. A) they cannot produce or store energy in the form of ATP and have to get their energy from the host cell. B) they parasitize the host cell for basic molecules like amino acids, nucleotides, and lipids. D) they lack DNA/RNA so they must use the DNA of the host cell. Address 立

Match each of the descriptions in Column A with the correct panel listed in Column B. Description Panel Resistant bacteria share resistance genes with each other Resistant bacteria survive and reproduce Treatment with methicillin kills nonresistant bacteria Some bacteria carry a mutation that provided resistance to methicillin Predict the possible outcome(s) if the antibiotic tetracycline was applied after panel 4. Check all that apply. O The tetracycline will act as a selective pressure, causing bacteria to mutate in order to survive. O Since the population is resistant to methicillin and not tetracycline, none of the bacteria will survive. O Treatment with an antibiotic will not affect the overall survival of the population. Any bacterium that has a mutation for tetracycline resistance would be able to survive.
Sp 23 E2.pdf bads/Sp%2023%20E2.pdf Read aloud E R x + + of 4 Q D 29) The life cycle of the virus that infects bacteria and allows the bacteria to survive is called: a) Phagic b) Recombinant c) lytic d) parasitic e) lysogenic 30) The enzyme present in the human immune virus which must be injected with the genetic material is called: a) Reverse Translatase b) Reverse Replicase c) Reverse Transcriptase d) Reverse Polymerase e) Retro Virase 31) If the electron donor for bacterial nutrient uptake is coming from H₂S then this mode of electron uptake is called: a) Electromotive trophy b) Electro-osmosis c) Lithotroph d) Heterotroph e) none of the above 32) The life cycle of the virus that infects bacteria and destroys the bacterial cell membrane: a) Phagic b) Cytotic c) Apoptotic d) lytic e) lysogenic. 3 33) If an organism feeds on dead or dying organisms that this mode of feeding is called: a) Heterotroph b) Chemoheterotroph c) Chemolithoautroph d) Chemolithoorganotroph e) Saprobic 34) One…
Plateau Phase Death Lag Phase Exponential Growth Phase Phase Fen ve cels Many ive cets Dead cells 10 15 20 25 30 35 40 45 Hours Consider the above figure which depicts the growth curve of microorganisms such as Saccharomyces cerevisiae. Now, reflect upon the components which make up the growth medium used to cultivate yeast. Whilst the growth medium was being made, the component which provides a source of energy for yeast was omitted. VWhat component was left out? What effect will this have on the growth curve phases and the rate at which they occur, especially in regard to the 'Exponential Growth' phase of the yeast? Loganmm/10of Vahie Cels
Katelyn had been working for Dr. Johnson for a month, and while she had become quite good at measuring inhibitionzones, she didn’t know why she was doing all this work. She had gotten very curious after she began doing all themeasurements on a new set of antibiotics. # is experiment involved infecting mice with MRSA and tracking how theMRSA grew over time.Data were collected by counting the cells of MRSA taken from $ uid samples from the mice. # e cells were measuredby taking one gram of the $ uid and spreading it over plates, but now Katelyn counted the colonies that grew on theplate after 24 hours. Because there were so many, she actually measured the colonies as “log CFU/g.” A CFU is acolony forming unit, or essentially a cell that will divide into a colony that can be seen. Because there can be so many,Katelyn measured them on a logarithmic (log) scale. # e raw data in her lab notebook looked like the following:Table 1. E% ect of treatment on MRSA in mice after 24 hours of drug…