
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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When monochromatic light of an unknown wavelength falls on a sample of zinc, a minimum potential of 2.21 V is required to stop all of the ejected photoelectrons. (The work function for zinc is 4.31 eV. Determine the maximum speed (m/s) and wavelength (nm).
Expert Solution

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Step 1
Given:
work function for zinc, Φ = 4.31 eV
Stopping potential, V = 2.21 V
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- What is the maximum velocity of a photoelectron emitted from a surface with work function 6.2 eV when illuminated by 181-nm ultraviolet light? ( m electron = 9.11 × 10 −31 kg, h = 6.63 × 10 −34 J ⋅s, 1 eV = 1.60 × 10 −19 J, and 1 nm = 10 −9 m)arrow_forwardFor a certain metal, the threshold wavelength for the photoelectric effect is 664.0 nm. What is the maximum velocity (in m/s) for ejected electrons when light with wavelength 464.0 nm shines on the metal?arrow_forward(a) A photoelectric experiment is performed where green light with a wavelength of 546.1 nm is shined on a metal plate, creating a photocurrent from it to a collector plate. When the potential difference between the metal plate and the collector is increased to a magnitude of 0.686 V, the photocurrent goes to zero—in other words, this is the stopping potential. What is the work function (in eV) for this metal? answer in eV (b) The experiment is performed again with the same metal, but now red light with a wavelength 650.0 nm is shined on it. What is the new stopping potential (in V) in this case? answer in Varrow_forward
- Lithium has a work function of 2.51 eV. What is the maximum kinetic energy of the photoelectrons if 9.7 x 10¹4 Hz radiation is incident upon it?arrow_forwardWhen monochromatic light of an unknown wavelength falls on a sample of silver, a minimum potential of 2.69 V is required to stop all of the ejected photoelectrons. (The work function for silver is 4.73 eV.) HINT (a) Determine the maximum kinetic energy (in eV) of the ejected photoelectrons. eV (b) Determine the maximum speed (in m/s) of the ejected photoelectrons. m/s (c) Determine the wavelength in nm of the incident light. nmarrow_forwardUV radiation having a wavelength of 146 nm falls on gold metal, to which electrons are bound by 4.82 eV. What is the maximum velocity of the ejected photoelectrons? No need to use relativistic formulas in this case.arrow_forward
- A beam of 400 nm light is adjusted to have the same intensity as a beam of 600 nm light. How does the number of photons in the 400nm beam, N400 compare to the number of photons, N600 in the 600 nm beam. Question 5 options: N400 = 2*N600 N400 = 32600 N400 = N600 N400 = 23600 N400 = 2600 None of the other responses are correct.arrow_forwardLight with a frequency of (1.99x10^15) Hz hits a metal with a work function of (4.200x10^0) eV. Determine the maximum velocity of photoelectrons generated by this setup.arrow_forwardAn experiment is performed where light of different frequencies is shined on an aluminum plate. The work function for aluminum is 4.08 eV. (a) What is the lowest frequency (the "cutoff" frequency, in Hz) of light incident on aluminum, below which no photoelectrons will be emitted from its surface? Hz (b) What is the longest wavelength (the "cutoff" wavelength, in nm) of light incident on aluminum, above which no photoelectrons will be emitted from its surface? nm (c) Photons of energy 5.75 eV are incident on the aluminum plate. What is the maximum kinetic energy (in eV) of the ejected photoelectrons? evarrow_forward
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