When given a particle’s position along the x-axis is described by the function x(t) = A t + B t2, where t is in seconds, x is in meters, and the constants A and B are given below. By given the variables below A = -3.6 m/s B = 3.5 m/s2   What would the expressions be, in terms of A, B, and t for the velocity of the particle as a function of time??

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Chapter1: Units, Trigonometry. And Vectors
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When given a particle’s position along the x-axis is described by the function
x(t) = A t + B t2,


where t is in seconds, x is in meters, and the constants A and B are given below.

By given the variables below
A = -3.6 m/s
B = 3.5 m/s2

 

What would the expressions be, in terms of A, B, and t for the velocity of the particle as a function of time??

My solution at first was 3.6 * 7.0 t.

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