College Physics
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Concept explainers

Displacement, Velocity and Acceleration
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Linear Displacement
The term "displacement" refers to when something shifts away from its original "location," and "linear" refers to a straight line. As a result, “Linear Displacement” can be described as the movement of an object in a straight line along a single axis, fo…
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Question

A certain person walks 80 cm north, 60 cm south and 30 cm north. What is the displacement?

size of the displacement _______  direction of the displacement  ________

 

**Physics Problems on Motion and Acceleration** 9. A car changes its velocity from 10 m/s to 40 m/s over a 4-second interval. - a. What is the car’s average velocity during this time? - b. What is the average acceleration of the car? 10. A truck traveling at 10 m/s accelerates at 3.5 m/s² for a period of 5 seconds. What is the velocity at the end of its period of acceleration? 11. To measure the height of the Tech Building Building, a physics student decided to drop a baseball off the roof. If it took the baseball 2.5 seconds to hit the ground, how tall is the building? 12. Steve is cruising on his blades at 4 m/s. He starts accelerating at 0.6 m/s². What is his speed after 4 seconds? After he has sped up for 4 seconds, he slows down at a rate of 1 m/s² for 1.5 seconds. How fast is he going at the end? 13. If you are driving 20 m/s down the street, what acceleration is needed to stop in 4 seconds? (Note: The image does not contain any graphs or diagrams, only text.)
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Transcribed Image Text:**Physics Problems on Motion and Acceleration** 9. A car changes its velocity from 10 m/s to 40 m/s over a 4-second interval. - a. What is the car’s average velocity during this time? - b. What is the average acceleration of the car? 10. A truck traveling at 10 m/s accelerates at 3.5 m/s² for a period of 5 seconds. What is the velocity at the end of its period of acceleration? 11. To measure the height of the Tech Building Building, a physics student decided to drop a baseball off the roof. If it took the baseball 2.5 seconds to hit the ground, how tall is the building? 12. Steve is cruising on his blades at 4 m/s. He starts accelerating at 0.6 m/s². What is his speed after 4 seconds? After he has sped up for 4 seconds, he slows down at a rate of 1 m/s² for 1.5 seconds. How fast is he going at the end? 13. If you are driving 20 m/s down the street, what acceleration is needed to stop in 4 seconds? (Note: The image does not contain any graphs or diagrams, only text.)
**Physics Problems and Solutions** **8. Projectile Motion** A bullet is shot from a rifle at a speed of 920 m/s. How long does it take to hit a target that is 3.24 km away? - **Solution:** - Convert 3.24 km to meters: 3.24 km = 3240 m - Use the formula: \( T = \frac{\text{distance}}{\text{velocity}} \) - Substitute the values: \( T = \frac{3240 \text{ m}}{920 \text{ m/s}} = 3.52 \text{ s} \) **9. Car Acceleration** A car changes its velocity from 10 m/s to 40 m/s over a 4-second interval. - **a. Average Velocity:** - Calculate using: \( \frac{10 \text{ m/s} + 40 \text{ m/s}}{2} = 25 \text{ m/s} \) - **b. Average Acceleration:** - Use the formula: \( a = \frac{\Delta v}{t} \) - Calculation: \( a = \frac{40 \text{ m/s} - 10 \text{ m/s}}{4 \text{ s}} = 7.5 \text{ m/s}^2 \) **10. Truck Acceleration** A truck traveling at 10 m/s accelerates at \(3.5 \text{ m/s}^2\) for a period of 5 seconds. What is the velocity at the end of acceleration? - **Solution:** - Use the formula: final velocity \( v = u + at \) - Calculation: \( v = 10 \text{ m/s} + (3.5 \text{ m/s}^2 \times 5 \text{ s}) = 27.5 \text{ m/s} \) **11. Measuring Building Height** To measure the height of the Tech Building Building, if a baseball is dropped from the roof and takes 2.5 seconds to hit the ground, how tall is the building? - **Solution:** - Use the formula: \( h = \frac{1}{2}gt^2 \) (where \( g = 9.8 \text{ m/s}^2 \)) - Calculation
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Transcribed Image Text:**Physics Problems and Solutions** **8. Projectile Motion** A bullet is shot from a rifle at a speed of 920 m/s. How long does it take to hit a target that is 3.24 km away? - **Solution:** - Convert 3.24 km to meters: 3.24 km = 3240 m - Use the formula: \( T = \frac{\text{distance}}{\text{velocity}} \) - Substitute the values: \( T = \frac{3240 \text{ m}}{920 \text{ m/s}} = 3.52 \text{ s} \) **9. Car Acceleration** A car changes its velocity from 10 m/s to 40 m/s over a 4-second interval. - **a. Average Velocity:** - Calculate using: \( \frac{10 \text{ m/s} + 40 \text{ m/s}}{2} = 25 \text{ m/s} \) - **b. Average Acceleration:** - Use the formula: \( a = \frac{\Delta v}{t} \) - Calculation: \( a = \frac{40 \text{ m/s} - 10 \text{ m/s}}{4 \text{ s}} = 7.5 \text{ m/s}^2 \) **10. Truck Acceleration** A truck traveling at 10 m/s accelerates at \(3.5 \text{ m/s}^2\) for a period of 5 seconds. What is the velocity at the end of acceleration? - **Solution:** - Use the formula: final velocity \( v = u + at \) - Calculation: \( v = 10 \text{ m/s} + (3.5 \text{ m/s}^2 \times 5 \text{ s}) = 27.5 \text{ m/s} \) **11. Measuring Building Height** To measure the height of the Tech Building Building, if a baseball is dropped from the roof and takes 2.5 seconds to hit the ground, how tall is the building? - **Solution:** - Use the formula: \( h = \frac{1}{2}gt^2 \) (where \( g = 9.8 \text{ m/s}^2 \)) - Calculation
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