When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x1010 N/m and the longitudinal stralin for the brass rod ist.96x103 useful equation: Poissons ratio = Lateral strain / Longitudinal strain O 0.63 O 031 1.11 O 0.92

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter7: Analysis Of Stress And Strain
Section: Chapter Questions
Problem 7.7.15P: A brass plate with a modulus of elastici ty E = 16 X 106 psi and Poisson’s ratio a = 0.34 is loaded...
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When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x100 N/m and the
longitudinal strain for the brass rod is1.96x103
useful equation: Poissons ratio = Lateral strain / Longitudinal strain
O 0.63
O 031
O 1.11
O 0,92
Transcribed Image Text:When a brass rod of diameter 2 mm is subjected to a tension of Sx10 N, the diameter changes by 3.6x104 cm. Calculate the Poisson's ratio for brass given that the Elastic modulus for the brass is 9x100 N/m and the longitudinal strain for the brass rod is1.96x103 useful equation: Poissons ratio = Lateral strain / Longitudinal strain O 0.63 O 031 O 1.11 O 0,92
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