When 3.848 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 13.21 grams of CO₂ and 2.164 grams of H₂O were produced. In a separate experiment, the molar mass of the compound was found to be 128.2 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =

Convert 1.36 x 10-18 grams of X3Z5 into molecules/formula units of the same compound. (Assume that the molar mass of X is 32.36 grams per mole and the molar mass of Z is 56.03 grams per mole.) Assume that Avogadro's number is 6.022 x 1023. Report your answer to three decimal places.

An unknown compound contains only CC , HH , and OO . Combustion of 8.60 g8.60 g of this compound produced 17.2 g17.2 g CO2CO2 and 7.03 g7.03 g H2OH2O . What is the empirical formula of the unknown compound? Insert subscripts as needed.

Combustion analysis of naphthalene, a hydrocarbon used in mothballs, produced 8.80 g CO2 and 1.44 g H2O. Calculate the empirical formula for naphthalene.

When 6.961 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 21.84 grams of CO₂ and 8.943 grams of H₂O were produced. In a separate experiment, the molar mass of the compound was found to be 28.05 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula = =

A 3.000 g sample of a gaseous compound was found to contain 2.560 g of carbon and 0.440 g of hydrogen. A) What is the simplest formula of the compound (Write C first and then H)? You won't be able to make the numbers a subscript. For instance, for MgCl2 enter MgCl2. B) The molar mass of the compound was found to be 42.08 g/mol. What is the molecular formula of the compound? You won't be able to make the numbers a subscript. For instance, for MgCl2 enter MgCl2.

When 4.007 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 12.14 grams of CO, and 6.212 grams of H20 were produced. In a separate experiment, the molar mass of the compound was found to be 58.12 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula = molecular formula =

When 6.608 grams of a hydrocarbon, C,Hy, were burned in a combustion analysis apparatus, 20.73 grams of CO2 and 8.489 grams of H,O were produced. In a separate experiment, the molar mass of the compound was found to be 70.13 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula molecular formula

Click in the answer box to activate the palette. Menthol is a flavoring agent extracted from peppermint oil. It contains C, H, and O. In one combustion analysis, 10.00 mg of the substance yields 11.53 mg H,0 and 28.16 mg CO2. What is the empirical formula of menthol? Add subscripts to complete the empirical formula. CHO

When 5.095 grams of a hydrocarbon, CxHy, were burned in a combustion analysis apparatus, 15.61 grams of CO₂ and 7.457 grams of H₂O were produced. In a separate experiment, the molar mass of the compound was found to be 86.18 g/mol. Determine the empirical formula and the molecular formula of the hydrocarbon. Enter the elements in the order presented in the question. empirical formula molecular formula = = Previous Next