Answered: When 1.00 g of AgCl is formed by the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

When 1.00 g of AgCl is formed by the reaction in a coffee cup calorimeter, the temperature of 20.0 g of water increases from 15.0 degrees celsius to 20.47 degrees celsius. Calculate

a) the amount of heat absorbed by the water

b) delta H when one mole of AgCl is formed by this reaction

Expert Solution

Introduction

$H e a t a b s o r b e d b y w a t e r c a n b e c a l c u l a t e d b y u \sin g t h e f o r m u l a : Q = m . C_{p} . ∆ T$

$\begin{array}{rcl} w h e r e, Q & = & h e a t a b s o r b e d / r e l e a s e d \\ m & = & m a s s o f s u b s \tan c e \\ C_{p} & = & s p e c i f i c h e a t c a p a c i t y \\ ∆ T & = & C h a n g e i n t e m p e r a t u r e \end{array}$

Part a

$G i v e n : M a s s o f w a t e r, m = 20.0 g S p e c i f i c h e a t c a p a c i t y o f w a t e r, C_{p} = 4.184 J g^{- 1} ° C^{- 1} C h a n g e i n t e m p e r a t u r e, ∆ T = 20.47 ° C - 15.0 ° C = 5.47 ° C Q = m . C_{p} . ∆ T Q = 20.0 g \times 4.184 J g^{- 1} ° C^{- 1} \times 5.47 ° C Q = 457.73 J \Rightarrow 457.73 J o f h e a t i s a b s o r b e d b y t h e w a t e r .$

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