What would be the period of revolution of a hypothetical planet whose circular orbit around the sun has a radius of 1.75 AU? (Hint: 1 AU = 1 Astronomical Unit = 1.5*1011) a) 2.3 yrs b) 1.45 yrs c) 2.9 yrs

When the Earth passes directly between the Sun and Mars, the Earth and Mars are closest to each other. If Mars is 1.52 AU from the Sun and there are 1.5 x 108 km in 1 AU, how many times will the width of the U.S. (2,530 miles) fit end-to-end between Mars and Earth? Planets and Sun not drawn to scale. Mars Earth Sun Part 1 of 4 Mars is 1.52 AU from the Sun. How many times further away from the Sun is Mars than the Earth? (The distances in AU are relative to the distance between the Sun and the Earth, so however many AU a planet is away from the Sun is how many times farther it is from Sun than Earth.) 1.52✔ 1.52 times further away

1. The diameter of the Sun is equal to 1.392*10^9 m, and the distance from the Sun to Saturnis equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system,and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer inmeters.b) The actual diameter of Saturn is 116,460 km. What would be Saturn’s diameter in yourscale model? Give your answer in centimeters.

1 AU = 1.496 x10^11 m

How many orders of magnitude do you need to grow in spatial scale (size) to form a planet? Let's take the extreme ends of this scale, from a dust particle of radius a = 10-6m to the gas giant Jupiter (you can round up its radius to the nearest ten to keep it simple). What else has this difference in order of magnitude? Maybe pick something that's not a length scale. Be creative!

Kepler's 1st law says that our Solar System's planets orbit in ellipses around the Sun where the closest distance to the Sun is called perihelion. Suppose I tell you that there is a planet with a perihelion distance of 2 AU and a semi-major axis of 1.5 AU. Does this make physical sense? Explain why or why not.

SnowT is an exoplanet orbiting star 27 Kood.  If the planet’s orbital period is 3.75 days and 27 Kood's constant is 2.9X10^-19 s^2/m^3, what is SnowT orbital radius?

The figure below is a scaled representation of a planet's orbit with a semimajor axis of 1.598 AU. (Use the exact values you enter in previous answer(s) to make later calculation(s).) (a) Find the ratio of the aphelion-to-perihelion distance. TA (b) Find the perihelion and aphelion distances in astronomical units. AU AU (c) Find the distance the Sun is from the center of the orbit. AU

The radius of the Earth's orbit is 1.50 x 1011 m and that of Pluto is 5.93 x 1012 m. The star that this planet orbits is identical to our Sun. What is the orbital period of this planet? years eBook

1. Moon is at the distance 384400 km from Earth and orbits the Earth every ~28 days. If the radius of the Moon is 1737 km (consider it to be spherical), what is the area of the moon as measured by the observer on Earth? (Hint: Length contraction)