Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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- struct insert_at_back_of_sll { // Function takes a constant Book as a parameter, inserts that book at the // back of a singly linked list, and returns nothing. void operator()(const Book& book) { /// TO-DO (3) /// // Write the lines of code to insert "book" at the back of "my_sll". Since // the SLL has no size() function and no tail pointer, you must walk the // list looking for the last node. // // HINT: Do not attempt to insert after "my_sll.end()". // ///// END-T0-DO (3) ||||// } std::forward_list& my_sll; };arrow_forwardConsider the following structure of a node for a linked list. struct Node { int key; Node *next; }; What will be the output of the following pseudo-code? Assume, head is a pointer to the first node of the following linked list. 5->2->8->2->9->2->11-> NULL Node *pres head; 0; while(pres!= NULL && Count key : int count 2) { count = count + 1; } pres = pres->next; } cout key « endl; 11 Error 2.arrow_forwardIn this code: #include <iostream> #include <string> using namespace std;// Node struct to store data for each song in the playliststruct Node { string data; Node * next;};// Function to create a new node and return its addressNode * getNewNode(string song) { Node * newNode = new Node(); newNode -> data = song; newNode -> next = NULL; return newNode;}// Function to insert a new node at the head of the linked listvoid insertAtHead(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return;} newNode -> next = * head; * head = newNode;}// Function to insert a new node at the tail of the linked listvoid insertAtTail(Node ** head, string song) { Node * newNode = getNewNode(song); if ( * head == NULL) { * head = newNode; return; } Node * temp = * head; while (temp -> next != NULL) { temp = temp -> next; } temp -> next = newNode;}// Function to remove a node from the linked listvoid removeNode(Node ** head,…arrow_forward
- what is the problem in the display function ? the code : #include <iostream>using namespace std; class node{public: int data; node* next;}; void display(node * head) // printing the data of the nodes{ node* temp = head; while (temp != NULL) { cout << temp->data << endl; temp = temp->next; }} // add void push(node** head, int newdata) // { 5, 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = *head; *head = newnode;} void append(node** head, int newdata) // { 10 , 20 , 30 , 40 }{ node* newnode = new node(); newnode->data = newdata; newnode->next = NULL; node* last = *head; if (*head == NULL) { *head = newnode; return; } while (last->next != NULL) { last = last->next; } last->next = newnode;} void insertafter(node*…arrow_forwardCreate a function that uses Node * pointing to root of AVL Tree as an input and returns the height of the AVL tree in O(log(n)).arrow_forward
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