Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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**Educational Website Transcription and Explanation:**

---

### Topic: Inverse Functions and Derivatives

**Function Analysis:**

The function \( f(x) = 15e^{-x} \sqrt{x} \) is shown below. We are examining its behavior for the restricted domain \( x \geq 0.5 \).

**Question 1:** Does the function appear to have an inverse function for this restricted domain? (DO NOT DERIVE IT!!)

- **Why or why not?**

**Question 2:** Estimate \( (f') (1) \): ______

- What then is the approximate derivative \( (f^{-1})'(x) \) at the point \(\left( \frac{15}{e}, 1 \right)\)?

- **Why? What theorem or rule supports your answer?**

**Graph Analysis:**

The graph of the function \( f(x) = 15e^{-x} \sqrt{x} \) is provided. Key features include:

- The graph decreases as \( x \) increases from 0.5.
- The plotted point (0.5, 6.133) is marked, indicating the function value at \( x = 0.5 \).

### Detailed Explanation:

1. **Does the function have an inverse?**

   A function has an inverse if it is one-to-one (bijective) in the specified domain. The graph shows a decrease in the value of \( f(x) \) as \( x \) increases from 0.5, suggesting that the function is one-to-one on this domain.

2. **Estimating \( f'(1) \):**

   - Examine the graph or utilize the derivative of the function \( f(x) \) to approximate \( f'(1) \). 

3. **Derivative of the Inverse:**

   - Use the formula for the derivative of the inverse function: 
     \[
     (f^{-1})'(y) = \frac{1}{f'(f^{-1}(y))}
     \]
   - Understand that this is supported by the Inverse Function Theorem, which states that if \( f \) is bijective and differentiable, then so is \( f^{-1} \).

By reviewing the graph and applying these concepts, we can analyze and estimate the behavior of both the function and its inverse.

---
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Transcribed Image Text:**Educational Website Transcription and Explanation:** --- ### Topic: Inverse Functions and Derivatives **Function Analysis:** The function \( f(x) = 15e^{-x} \sqrt{x} \) is shown below. We are examining its behavior for the restricted domain \( x \geq 0.5 \). **Question 1:** Does the function appear to have an inverse function for this restricted domain? (DO NOT DERIVE IT!!) - **Why or why not?** **Question 2:** Estimate \( (f') (1) \): ______ - What then is the approximate derivative \( (f^{-1})'(x) \) at the point \(\left( \frac{15}{e}, 1 \right)\)? - **Why? What theorem or rule supports your answer?** **Graph Analysis:** The graph of the function \( f(x) = 15e^{-x} \sqrt{x} \) is provided. Key features include: - The graph decreases as \( x \) increases from 0.5. - The plotted point (0.5, 6.133) is marked, indicating the function value at \( x = 0.5 \). ### Detailed Explanation: 1. **Does the function have an inverse?** A function has an inverse if it is one-to-one (bijective) in the specified domain. The graph shows a decrease in the value of \( f(x) \) as \( x \) increases from 0.5, suggesting that the function is one-to-one on this domain. 2. **Estimating \( f'(1) \):** - Examine the graph or utilize the derivative of the function \( f(x) \) to approximate \( f'(1) \). 3. **Derivative of the Inverse:** - Use the formula for the derivative of the inverse function: \[ (f^{-1})'(y) = \frac{1}{f'(f^{-1}(y))} \] - Understand that this is supported by the Inverse Function Theorem, which states that if \( f \) is bijective and differentiable, then so is \( f^{-1} \). By reviewing the graph and applying these concepts, we can analyze and estimate the behavior of both the function and its inverse. ---
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