Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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What should the loading factor be (on ANY HASH TABLE) if you want to have an average of 1.4 comparisons per successful search if LINEAR PROBING?
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- However, our hash map was poorly constructed, so all of the values are now in the same pile (that is, they are all in the same LinkedList). To what extent does this defeat the purpose of a hash map, please explain.arrow_forwardAssume that linear probing is used for hash-tables. To improve the time complexity of the operations performed on the table, a special AVAILABLE object is used to mark a location when an item is removed from the location. Assuming that all keys are positive integers, the following two techniques were suggested instead of marking the location as AVAILABLE: i) When an entry is removed, instead of marking its location in the table as AVAILABLE, indicate the key in the location as the negative value of the removed key (e.g., if the removed key was 16, indicate the key as -16). Searching for an entry with the removed key would then terminate once a negative value of the key is found (instead of continuing to search if AVAILABLE is used). ii) Instead of using AVAILABLE, find a key in the table that should have been placed in the location of the removed entry, then place that key (the entire entry of course) in that location (instead of setting the location as AVAILABLE). The motive is to…arrow_forwardJava - Hash table valsTable uses quadratic probing, a hash function of key % 10, c1 = 1, and c2 = 1.arrow_forward
- A hash-map has been constructed with double-hashing by applying h;(k;) = [h(k;) + jd(k;)] mod N. The primary hashing function is given as h(k;) hashing function as d;(k;) = k;divN where div is integer division. The maximum number of cells probed is N = 13. How many cells will be probed by the call of findElement(38) = k;modN and the secondary Note: The first row contains the indices and the second row contains the elements. 1 2 4 5 6. 7 8 10 11 12 27 14 available 6. 35 25 51arrow_forwardInsert the following sequence of keys in the hash table.Keys = {4, 2, 1, 3, 5, 6, 8}Use linear probing technique for collision resolution: h(k, i) = [h(k) + i] mod mHash function, h(k) = 3k + 1Table size, M = 10 Draw the hash table, compute the index where the hashvalue will be inserted for each key, and show how you would use the technique when a collisionoccurs.arrow_forwardGive the contents of a linear-probing hash table that results when you insert thekeys E A S Y Q U T I O N in that order into an initially empty table of initial size M= 4 that is expanded with doubling whenever half full. Use the hash function 11 k % Mto transform the kth letter of the alphabet into a table index.arrow_forward
- Given the hash function H (key) = (3 * key) mod 11, use square probe to solve the conflict. Please construct a hash table for the keyword sequence {6,8,10,17,20,23,33,41,59,60} in the hash table whose length is 11.arrow_forwardIf your hash map is flawed, random integers will be lumped together (in the same LinkedList) even if they have no obvious connection. Explaining how this works will allow you to defeat hash maps.arrow_forwardSuppose we use a hash function h to hash n distinct keys into an array T oflength m. Assuming simple uniform hashing, what is the expected number ofcollisions? More precisely, what is the expected cardinality of ffk; lg W k ¤ l andh.k/ D h.l/g?arrow_forward
- What is the average-case runtime required for a successful operation in a hash table using chaining where there are m buckets and n items in the hash table? Select one: a. O( n/m ) b. O(n) The answer depends on both n and m c. O( 1) d. O(m)arrow_forwardhow do I approach this question? Can you show me step by step Please.arrow_forwardGiven a hash table of size M=10 and a linear probing method, following are the contents of the hash table: [-1, 41, 71, -1, 64, 75, 84, -1, 88, 9]. -1 indicates slot is empty. Use the standard hash function: h(x)=x%M Match the index on the left with the value on the right for the hash table after the following operations are carried out in the given order: delete(88) delete(41) delete(44) insert(108) insert(71)arrow_forward
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