What is the p-value of a left-tailed one-mean hypothesis test, with a test statistic of z0=−1.19? Use a p-value rounded to 3 decimal places. Here is a portion of the Standard Normal Table. To read the Standard Normal table, match the ones and tenths digits of the z-value in the first column with the correct hundredths digit in the first row. z 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 -1.4 0.081 0.079 0.078 0.076 0.075 0.074 0.072 0.071 0.069 0.068 -1.3 0.097 0.095 0.093 0.092 0.090 0.089 0.087 0.085 0.084 0.082 -1.2 0.115 0.113 0.111 0.109 0.107 0.106 0.104 0.102 0.100 0.099 -1.1 0.136 0.133 0.131 0.129 0.127 0.125 0.123 0.121 0.119 0.117 -1.0 0.159 0.156 0.154 0.152 0.149 0.147 0.145 0.142 0.140 0.138

A new material will replace the old material only if there is significant evidence that the mean strength of the new material is more than 2 units higher than the mean strength of the old material.        Sample from new material:     mean  is  98.064   ,     SD  is   5.6     and sample size is 13 Sample from old material:       mean  is  95.282   ,     SD  is   5.8      and sample size is 78 We do not know population standard deviations. Consider the test           ?0:????−????=2H0:μnew−μold=2   vs.  ?0:????−????>2H0:μnew−μold>2  What is the p-value?       (Hint:  best to use software, or else the Desmos Calculator for the 2 sample T and Z test)  Give as a decimal between 0 and 1 accurate to at least 4 decimal places.

Due in Testing: Ho: u = 40.26 H1: u # 40.26 Your sample consists of 29 subjects, with a mean of 42.1 and a sample standard deviation (s) of 4.48. Calculate the test statistic, rounded to 2 decimal płaces.

what is the standard normal curve that lies between -1.11 and 1.11

How do you find (b.)?

For a sample, a score that is 12 points above the mean has a z-score of z = 1.20. What is the sample standard deviation?

= Scores on a standardized exam are known to follow a normal distribution with standard deviation o 8.2. A researcher randomly selects 100 students and computes their average score. He reports that the mean score is 83, with a margin of error of 1.436. How confident are you that the mean score for all students taking the exam is in the interval (81.564, 84.436)?

H0:μ=38.935H0:μ=38.935H1:μ≠38.935H1:μ≠38.935Your sample consists of 31 subjects, with a mean of 38.5 and standard deviation of 4.13.Calculate the test statistic, rounded to 2 decimal places. t=t=