What is the period of small oscillations for a simple pendulum of length L=4 m if it is placed in a car that is accelerating horizontally at 4m/s2?
Q: The motion of a particle is given by x(t)=(8) cm Cos(13t), where t is in s. What is the first time…
A: WE KNOW THAT
Q: By what factor has the acceleration changed due to gravity if the length is doubled and the period…
A: We know that time period of a simple pendulum is given as T=2πLg Where, L is the length of the…
Q: A pendulum has a weight of 1.7 pounds and a length of 3 feet. How long will it take for it to make…
A: HERE WE USE THE FORMULA OF TIME PERIOD OF SIMPLE PENDULUM.
Q: A geologist uses a simple pendulum that has a length of 29 cm and a frequency of 0.841 Hz at a…
A: The time period is given as T = 1/f T = 1/0.841 T = 1.189 s
Q: Consider a 2.2 kg mass attached to a spring that glides back and forward on a smooth, frictionless,…
A: Part (1): Given: The mass of the object is 2.2 kg. The spring constant is 1.4 N/m.
Q: What will be the length of seconds pendulum at a point where g = 980cm/s²?
A: To Find: Length of second pendulum Given: For second pendulum T=2 sec g=980 cm/s2, g=9.8 m/s2
Q: A pendulum clock that works perfectly on Earth is taken to the moon, where g = 1.63m/s2. If the…
A: Calculate the ratio of periods of the pendulum on the moon and earth. TMoonTearth=gearthgmoon…
Q: When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s4) is moved to a new…
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Q: Geologists use pendulums to find tiny differences in the earths gravitational field from one…
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Q: At a certain location, the period of a 2.5m long pendulum is 3.6 seconds. What is the acceleration…
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Q: The motion of a particle is given by x(t) = (24cm)cos(10t) where t is in s. what is the first time…
A: Givenx(t)=(24 cm)cos(10 t)velocity, v(t)=dxdt =-(240 cm)sin(10 t)maximum…
Q: Figures 7.12 and 7.13 describe the motion of two differ- ent weights, A and B, attached to two…
A: a) When the weight is not in motion, the weight will be at the equilibrium position, i.e., the…
Q: The period of a simple pendulum of lengtg 1 meter, on another planet is 1.66 seconds. what is the…
A: Length of the pendulum is L = 1 m Time period of the pendulum is T = 1.66 s
Q: A simple pendulum is 1.15 meters long and has a period of 6.29 seconds. The pendulum is on an…
A: Let L is the length of the pendulum and g is the gravitational acceleration. The expression for the…
Q: A 7 kg mass attached to a horizontal spring oscillates at a frequency of 7 Hz. At t =0 s, the mass…
A: Period = 1/frequency
Q: The motion of a particle is given by x(t) = (25cm)cos(10t) where t is in s. what is the first time…
A: Given, The motion of the particle is given by, x(t) = 25 cm cos10 t -----(1) we have to evaluate…
Q: A mass m = 6.6 kg hangs on the end of a massless rope L = 2.04 m long. The pendulum is held…
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Q: Two high precision pendulums move through their equilibrium positions once each second, so that the…
A: Answer:- Given Period of each oscillation (T) = 2.000 s Length of Sweden(L1) = 0.99542 Length of…
Q: Consider two oscillating systems with equal periods on the Earth's surface: a simple pendulum (small…
A: Given: two oscillating system: 1: A simple pendulum = period Tp 2 A spring block system = period Tm
Q: moon, where g = 1.63m/s². If the clock starts at 10:07PM, what %3! will it read after 36 hours?
A: The time period of a pendulum is determined by the equation T=2πLg for the same…
Q: A group of astronauts, upon landing on planet X, performed a simple pendulum experiment in the MHS…
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Q: A mass falls from a height 'h' and its time of fall 't' is recorded in terms of time period T of a…
A: Hight= htime = tTime period of simple pendulum = TOn earth's surphase, t = 2TMass of the other…
Q: A simple pendulum on the Moon has a length of 1.45m and a corresponding period of 5.93 seconds. What…
A: To determine the gravitational acceleration on the moon, we will use equation for time period of…
Q: A 100 kg bob is attached to a 1 m long string. The pendulum has a period of 2 s. If this pendulum…
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Q: A pendulum bob swings through an arc 40 cm long on its first swing. Each swing thereafter, it swings…
A: For the first swing the distance =40cmthe second swing the distance =0.8×40cmthe third swing the…
Q: A mass hanging from a spring is set in motion and its ensuing velocity is given by v(t) = - 4t sin…
A: The equation of velocity :v(t) = - 4πsin πt s(0) = 4
Q: The position of an oscillating object in m is described by x = 3.50 cos πt, where t is in seconds.…
A:
Q: A frictionless pendulum of mass m=1 kg and length L=1 m, gets released at t=0 from a distance x=0.12…
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Q: 3. A pendulum is placed on another planet. The pendulum's arm is 2.0 meters long. The mass of the…
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Q: The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a…
A: Please see the attached image for the solution.If there are queries, please do not hesitate to ask.…
Q: Q. 3) A ball of mass 500 g is fastened to a string 1.2 m long and suspended from a fixed- point P to…
A:
Q: The spaceship Intergalactica lands on the surface of the uninhabited Pink Planet, which orbits a…
A: The objective of the question is to calculate the acceleration due to gravity (gpp) on the Pink…
Q: A ballerina prepares to entera spin.She swings her extended arms and one extended leg around, jumps…
A: Given information: The speed of rotation when the ballerina's arms and legs are extended is 1 sec;…
Q: The displacement of an oscillating mass is given by x(t) = 10 cos( 4 t). At time t = 2n s, what is…
A: Given, Displacement of an oscillating mass - x(t) =10 cos (4t) We need to find, Acceleration of…
Q: A string breaks if it’s tension exceeds 100N. What maximum speed a stone attached to the string…
A: The tension should be equal to centripetal force exerted on the string for maximum safest speed,
Q: A 1 kg pendulum is held 2 meters above the ground and released. How fast is the pendulum traveling…
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Q: 21 Time-dependent force AS-kg mass moves under the influence of a force F (4i-3¢])N, where r is the…
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Q: Problem 9: An ideal pendulum of length L= 1.1 m supports a mass of m =0.5 kg. Initially the pendulum…
A: Given data: Length (L) = 1.1 m Mass (m) = 0.5 kg Angle (θ) = 26° with vertical Initial velocity (v0)…
Q: Length (cm) t1 t2 t (average ) T( time period ) T^2 50 1.41 1.41 60 1.5 1.6 70 1.75 1.65 80 1.87 1.7…
A: Here we are supposed to find acceleration due to gravity. For this we use the time period equation…
Q: the mass is 10Kg and the constants have the values k1=100N/m, k2= 200N/m, k3= 300N/m, k4=400 N/m.…
A: Visualize the problem:
Q: Suppose a teacher is riding a Ferris wheel. The maximum height they attain is 30 m and the minimum…
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