What is the molecular weight of bis(tetraethylammonium) tetrabromocobaltate(II) and calculate the charge on the Co ion.

a) Consider the following two cobalt complexes: [Co(H2O)2(OH)4] Complex A [Co(CO)6] 3+ Complex B (i) Draw the d-electron configuration for A and B. Label each set of orbitals. (ii) Explain how the d-electron configuration changes when cobalt is replaced by iridium in A and B. (iii) Calculate the CFSE for A and B. Show all calculations and units. (iv) Which of these two complexes (A or B) will interact with a magnet? Motivate your answer.

Sketch a fully labelled energy level diagram for [Cr(H2O)6]3+, showing the d-orbitals and how they are occupied by electrons.

Name the following according to the rules provided in this course: a) Nag[FeBr] b) [Cr(CN)2(H2O)]²+ c) [COC12(NH3)(en)2]CI Give formulas for the following according to the rules provided in this course: d) dihydroxotetraaquaaluminum (IV) ion e) lithium tetranitrodiaminozincate (II)

Draw the d orbital electronic configuration of [Cr(co)6]3+  how many unpaired electrons are present  if six Br- groups were substituted for the six co groups to give [Cr(Br)6]3+ Would you expect CFSE to increase or decrease and why

(a) Draw the electronic configuration of [NiCl6]3. (b) Determine whether its paramagnetic or diamagnetic. (c) What is expected to happen to the color if the ligand is replaced by carbonyl?

When the copper (II) sulphate solution is reacted with a bidentate ligand such as ethylenediamine (en), the same thing would have happened. However, since one bidentate ligand has two donor atoms (Brown et al, 2017), each Cu2+ ion would only have 3 ligands at most, instead of 6 when reacted with monodentate ligands. The equation of the reaction is as follows: [Cu(H2O)6]2+(aq) + 3en(aq) → [Cu(en)3](aq) + 6H2O(ℓ)   a. How do we know how many ligands can enter? b. Explain briefly the discussion above.

For  [Co(H2O)6]2+ , Discuss the similarities/dissimilarities in the magnetic moment values with experimentally determined values of 5.0 and 4.4 µB for octahedral and tetrahedral complexes, respectively.

why does [Mn(terpy)2]2+ have an electron configuration of high spin d5 instead of low spin d5