What is the magnitude of an upward electric field in which the electric force on a proton is equal in magnitude to its weight?

A proton is released from rest in a uniform electric field of magnitude 346 N/C. (a) Find the electric force on the proton. magnitude      N direction      ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero. (b) Find the acceleration of the proton. magnitude      m/s2 direction      ---Select--- in the direction of the electric field in the opposite direction of the electric field The magnitude is zero. (c) Find the distance it travels in 1.96 ?s. cm

Charge q, = 2.50 nC is at x, = 0 and charge q, = 6.00 nC is at x, = 4.00 m. At what point between the two charges is the electric field equal to zero? (Enter the x coordinate in m.) HINT Write an expression for the net electric field as a function of position, x, in the region between the two charges. (Don't forget that the electric field is a vector, so direction is important!) Set this expression equal to zero and solve for the variable x using the quadratic equation. Click the hint button again to remove this hint. m

A 1.86  10-9 C charge has coordinates x = 0, y = −2.00; a 3.21  10-9 C charge has coordinates x = 3.00, y = 0; and a -5.20  10-9 C charge has coordinates x = 3.00, y = 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin. (a) Determine the magnitude and direction for the electric field at the origin (measure the angle counterclockwise from the positive x-axis). magnitude   direction  ° (b) Determine the magnitude and direction for the instantaneous acceleration of a proton placed at the origin (measure the angle counterclockwise from the positive x-axis). magnitude   direction  °