An electron has an initial speed of 6.31 106 m/s in a uniform 4.22 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) How far does the electron travel before coming to rest? (b) How long does it take the electron to come to rest? (c) What is the electron's speed when it returns to its starting point?

An electron has an initial speed of 8.14 × 106 m/s in a uniform 5.31 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity O same direction as the electron's initial velocity not enough information to decide (b) How far does the electron travel before coming to rest? (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/s

An electron is accelerated by a constant electric field of magnitude 285 N/C. (a)Find the acceleration of the electron.   (b)Use the equations of motion with constant acceleration to find the electron's speed after 1.10  10-8 s, assuming it starts from rest.

An electron is placed at rest in an electric field of 510 N/C. Which of the followings is the speed of the electron 47.0 ns after being released? ( e = 1,6 × 10-19C,e, = 8,85 × 10-12c²/N.m², mej= 9,11× 10-31kg, m, = 1,67 × 10-27kg) Your answer: O A)1.4 x 105 m/s O B) 0.8 x 106 m/s O ) 0.3 x 104 m/s O D) 2.6 x 106 m/s O E)4.2 x 106 m/s

Air breaks down (loses its insulating quality) and sparking results if the field strength is increased to about 3.0 x 106 N/C. a) What acceleration does an electron experience in such a field (me=9.11x10’31kg)? (b) if the electron starts from rest, in what distance does it acquire a speed equal to 10% of the speed of light (3x107 m/s)?

If a proton is accelerating from rest in a smooth electric field of 480 N / C, what is the kinetic energy of this proton at t = 1.3x10 ^ -5s? (Calculate by a factor of x10 ^ -15 J) A) 0.8 C) 1.4 B) 1.7 D) 0.3 E) 1.0

A proton accelerates from rest in a uniform electric field of 642 N/C. At some later time, its speed is 1.50 x 106 m/s. (a) Find the magnitude of the acceleration of the proton. m/s² (b) How long does it take the proton to reach this speed? μs (c) How far has it moved in that interval? (d) What is its kinetic energy at the later time? Need Help? Master It

An electron has an initial speed of 5.21 x 106 m/s in a uniform 4.69 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/s

An electron is accelerated by a constant electric field of magnitude 305 N/C. (a) Find the acceleration of the electron.   (b) Use the equations of motion with constant acceleration to find the electron's speed after 7.50  10-9 s, assuming it starts from rest.

A proton accelerates from rest in a uniform electric field of 657 N/C. At some later time, its speed is 1.25 x 106 m/s. (a) Find the magnitude of the acceleration of the proton.(b) How long does it take the proton to reach this speed?(c) How far has it moved in that interval?(d) What is its kinetic energy at the later time?