What is the magnitude force on a proton moving at 2.5x10^5 m/s in a magnetic field 0.5T. If the velocity and magnetic field are perpendicular to each other?

A powerful, superconductive wire carries a 5000A current directly out of this screen. An electron is travelling parallel to the wire with a speed of 5E8 m/s, in the same direction as the current. the electron is 50.0 (micrometer) to the right of the wire.  A) What is the magnitude and direction of the Magnetic field due to the superconductor at the location of the electron? B) What is the magnitude and direction of the force acting on the electron due to the superconductor's magnetic field?

A charged particle moves in a magnetic field with a velocity of 300 m/s at an angle of 60 degrees to the magnetic field lines. If the charge on the particle is 1.5 μC and the magnetic field strength is 0.4 T, calculate the magnetic force acting on the particle.

A straight wire carries a current of 10.0 A at an angle of 30° with respect to the direction of a uniform magnetic field.  The wire feels a magnetic force in of 1.50N along each meter of its length.  What is the strength of the magnetic field?  Express your answer in Teslas.

A beam of electrons is accelerated from rest through a 134-V potential beam then enters a uniform magnetic field and follows a circular path of radius r = 21.9 cm in the field region. a) What is the angle between the magnetic field and the electrons velocity?  b) What is the magnitude of the magnetic field?

A wire is carrying a current of 3.6A  is placed in an external magnetic field of 6.7T. The magnetic field runs parallel to the current in the wire. The magnetic field interacts with a 8.3meter length of the wire. What is the force on the wire?

In 1897, the English physicist J. J. Thomson used crossed electric and magnetic fields to measure the charge to mass ratio of electrons. (A) Determine the ratio in SI units. (B) Determine the charge to mass ratio of a proton. (C) In one experiment, electrons are accelerated to speed v by an electric field E, and are then deflected by a magnetic field B. For the parameters given below, calculate the radius of the circular arc in the magnetic field. electric field = = 2.85 kV/cm; distance of the acceleration = 0.84 m; magnetic field = 0.08 T ]

An electron moves with a speed of  5.0×107 m/s in the directions shown in (Figure 1) and (Figure 2) below. A 0.40 T magnetic field points in the positive x-direction.What is the magnitude of the magnetic force in (Figure 2)?

An electron with a speed of 2.5 x 106 m/s moves with a circle in a plane perpendicular to a uniform magnetic field. If the radius of the circle is 2.3 cm, then what is the magnitude of the field?