What is the force F, on the charge located at x = 8.000 cm in the figure given that q = 2.250 µC? The other two chargesare located at 3.000 cm and 11.00 cm. Take the positive direction as pointing to the right. The Coulomb constant is8.988 x 10° N-m?/c?.+q-29+q++5.00010.00x (cm)Fx =N

Answered: What is the force F, on the charge…

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 65P

See similar textbooks

Related questions

Concept explainers

Question

What is the force F, on the charge located at x = 8.000 cm in the figure given that q = 2.250 µC? The other two charges
are located at 3.000 cm and 11.00 cm. Take the positive direction as pointing to the right. The Coulomb constant is
8.988 x 10° N-m?/c?.
+q
-29
+q
+
+
5.000
10.00
x (cm)
Fx =
N

Expert Solution

Step 1

For two charges, the electrostatic force between them is given by Coulomb's Law.

$F = k \frac{q_{1} q_{2}}{r^{2}}$

In the equation $r$ is the distance between the charges, $k$ is the coulomb's constant and $q_{1}, q_{2}$ are the charges.

On the left side the force due to the charge is towards left side that is negative $x$ direction. Force due to the charge on the right side is towards the right that is positive $x$ direction. Thus the total charge $- 2 q$ is given by:

$F_{x} = - k \frac{q_{2} q}{{r_{1}}^{2}} + k \frac{q_{2} q}{{r_{2}}^{2}}$

The given charge is $q = 2.250 μ C = 2.250 \times 10^{- 6} C$

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

Similar questions