What is the confidence level (1 - a) of the following confidence interval for μ: (x-1.96(),x+1.96()) (1-α)= (enter the number with 3 decimals)
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- Respiratory Rate Researchers have found that the 95 th percentile the value at which 95% of the data are at or below for respiratory rates in breath per minute during the first 3 years of infancy are given by y=101.82411-0.0125995x+0.00013401x2 for awake infants and y=101.72858-0.0139928x+0.00017646x2 for sleeping infants, where x is the age in months. Source: Pediatrics. a. What is the domain for each function? b. For each respiratory rate, is the rate decreasing or increasing over the first 3 years of life? Hint: Is the graph of the quadratic in the exponent opening upward or downward? Where is the vertex? c. Verify your answer to part b using a graphing calculator. d. For a 1- year-old infant in the 95 th percentile, how much higher is the walking respiratory rate then the sleeping respiratory rate? e. f.4 Let f(x) = (1/10)(x-3)^2 for x = 1, 2, 3, 4, 5 %3D Find the standard deviation of X. For the instructor, this was question 11. / 1.8 X 3.1 X 3.4 X 3.5 X 9.4 X 12.4In this exercise you will determine how many data values you’ll need to collect so that the true voltage is within the given variation from the collected data average, i.e. the true voltage is within the interval ± given variation, with a given level of confidence. Suppose you desire the true voltage to be within 0.01V of the collected data average with 90% confidence, i.e. Set p = 0.9 Determine α/2 = (1 - p)/2Do reverse lookup in a Z table, or use Excel function NORM.INV(0.95,0,1). Also, you must have a value for σ, the population standard deviation. For this question, assume it is 0.028. Next, rearrange the equation to solve for N.
- = = A dietician selected a random sample of n 50 male adults and found that their average daily intake of dairy products was x 756 grams per day with a standard deviation of s 35 grams per day. Use this sample information to construct a 95% confidence interval for the mean daily intake of dairy products for men.Calculate the test-statistic, t with the following information.n1=45n1=45, ¯x1=2.55x¯1=2.55, s1=0.4s1=0.4n2=55n2=55, ¯x2=2.85x¯2=2.85, s2=0.38s2=0.38Rounded to 2 decimal places.You want to compute a 90% confidence interval for the mean of a population with an unknown population standard deviation. The sample size is 20. The value of t* you would use for this interval is (a) 1.699 (b) 1.725 (c) 1.729 (d) 1.845 (e) 1.9 (f) None of the above
- The sample mean was given to be x = $253.45 spent per day and the sample standard deviation was given to be s = $75.50. The value of ta/2 was determined to be 1.998. All the values are now known to construct the confidence interval. S The lower bound of the confidence interval is calculated using the expression x-ta/2 √n Find this lower bound, rounding the result to two decimal places. lower bound = x-ta/2 = 253.45 1.998 Ei S upper bound = x + ta/2 √n The upper bound of the confidence interval is calculated using the expression x + ta/2 to two decimal places. 75.50 = 253.45 + 1.998 √64 75.50 √64 S √n Find this upper bound, rounding the result 74°F Sunny 4:18 PM 4/17/2023 ĘSuppose that a researcher estimated a regression model and obtained a 95 % confidence interval for a parameter equal to -1.02; 0.33}. Suppose that he estimates the same model with a number of observations that is four times larger than the original one. You expect the width of the confidence interval: O (a) to increase by a factor of 4 O (b) to decrease by a factor of 2 (c) to decrease by a factor of 4 O (d) None of the aboveFor the situation described below, state the null and alternative hypotheses to be tested. (Enter != for ≠ as needed.)A researcher wishes to show that a modified treatment decreases the mean time to recovery ?, which is currently 7 days.
- Suppose X-N(10,sigma=2), what is the z-score of x = 7.After 22 people used product A for a month, 17 people were satisfied and 5 people were not satisfied. Find the HPD interval of 95% of 0 when the pre-distribution of satisfaction 0 of this product is Beta(1,1).Consider the data in the table in Ex 9.16. (photo attached) Does the data provide significant evidence at the 3.9% level, to indicate that the population mean time among schizophrenics exceeds the population mean time among normal individuals by more than 15.0?(zobs =3.612, z.039 =1.76 )