What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the F2 pressure is 4.00×104 atm, the F concentration is 1.33M, and the Ca2+ concentration is 1.14M ? F2(g) + Cd(s)→2F(aq) + Cd²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:| : What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the F2 pressure is 6.11×104 atm, the F¯ concentration is 1.39M, and the Pb?* concentration is 1.01M ? F2(8) + Pb(s)2F(aq) + Pb²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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В.
What is the calculated value of the cell potential at 298K for
an electrochemical cell with the following reaction, when the
F2 pressure is 4.00×104 atm, the F¯ concentration is 1.33M,
and the Cd2+ concentration is 1.14M ?
F2(g) + Cd(s)2F(aq) + Cd²*(aq)
Answer:
The cell reaction as written above is spontaneous for the
concentrations given:|
|
c. What is the calculated value of the cell potential at 298SK for
an electrochemical cell with the following reaction, when the
F2 pressure is 6.11×104 atm, the F" concentration is 1.39M,
and the Pb2+ concentration is 1.01M ?
F2(9) + Pb(s)2F(aq) + Pb²*(aq)
Answer:
The cell reaction as written above is spontaneous for the
concentrations given:
Transcribed Image Text:В. What is the calculated value of the cell potential at 298K for an electrochemical cell with the following reaction, when the F2 pressure is 4.00×104 atm, the F¯ concentration is 1.33M, and the Cd2+ concentration is 1.14M ? F2(g) + Cd(s)2F(aq) + Cd²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:| | c. What is the calculated value of the cell potential at 298SK for an electrochemical cell with the following reaction, when the F2 pressure is 6.11×104 atm, the F" concentration is 1.39M, and the Pb2+ concentration is 1.01M ? F2(9) + Pb(s)2F(aq) + Pb²*(aq) Answer: The cell reaction as written above is spontaneous for the concentrations given:
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