What is the average height of 300 students in an instructor's class? To determine this, the instructor measures the heights of 30 students selected at random, obtaining a 95% confidence interval for the average height from 64.9 to 67.2 inches. b)What is the sample mean and margin of error?(Round to two decimal places)

Q: The confidence interval for a population porportion is (0.34, 0.52). What is the sample proportion…

A: From the provided information Confidence interval is (0.34, 0.52)

Q: Use the sample data and confidence level given below to complete parts (a) through (d). In a study…

A: From the provided information, Sample size (n) = 2598 Among which 913 were returned that is x = 913…

Q: A research institute poll asked respondents if they acted to annoy a bad driver. In the poll, n =…

A:

Q: Calculate the lower 95% confidence interval for the population mean. (round to the nearest tenth)…

A: given data n = 31σ2 = 15∴σ = 15 = 3.873x¯ = 5695% ci for μ = ?

Q: During the nutrition research, the amount of consumed kilocalories per day was measured for 18…

A:

Q: The confidence interval was (41%, 45%) What was the margin of error? +/- % What was the summary…

A:

Q: a. How many of the 3039 subjects used at least one prescription medication? (Round to the nearest…

A: Given : Total sample size of the survey  = 3039 Out of the sample, proportion of people who have…

Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

A: Solution: From the given information, n=32, d-bar=1.358, α=0.05 and sd=0.635.

Q: Use the confidence interval to find the margin area (.596,.740)   margin of error?  samplemean?

A: Given confidence interval is (.596,.740) margin of error=? sample mean=?

Q: In a study of 480 households, 168 households were found to have 4 cell phones. Find a 95% confidence…

A: Given: x=168 n=480 p^=xn=168480=0.35

Q: How do I calculate a 95% confidence level for a sample proportion in excel? Meaning, what formula…

A: Given : Confidence level = CL = 95% = 0.95

Q: You must estimate the mean temperature (in degrees Fahrenheit) with the following sample…

A: Obtain the 99% confidence interval for the population mean temperature. The 99% confidence interval…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Step 1: Given informationConfidence level, c = 0.90Margin of error, E = 0.05 Step 2: Part (a)The…

Q: UCLA would like to conduct a study to estimate the proportion of all UCLA students attending…

A: The value of margin of error is, Critical values: Using the z-table, the critical value at 98%…

Q: In a survey of 2405 adults in a recent​ year, 1217 say they have made a New Year's resolution.…

A: Given: n=2405 x=1217

Q: 3. Here are three confidence intervals for a proportion, all resulting from the same dataset: (0.83,…

A: Basics: As we know that the confidence level increases  the critical value also increases,  due to…

Q: Suppose the 90% confidence interval for a population mean is (20, 55). What is the point estimate…

A:

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: given data, E= 2%CI=0.90α=1-0.90=0.10for 90% CI, z-critical value:Zc:=Z0.10/2=Z0.05=1.645 [ from…

Q: Use the sample data and confidence level given below to complete parts (a) through (d). A research…

A: Solution: a. From the given information, n=2419 and X=1183.

Q: Refer to the data below: To estimate the mean height of female high school juniors, you take a…

A: Solution: Given data Sample size(n) = 30 To find : Point Estimate  of mean (μ) =??

Q: When 307 college students are randomly selected and surveyed, it is found that 128 own a car. Find a…

A: Given Data Sample Size, n = 307 Number of successes, x = 128 Significance level,…

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: margin of error(E)=0.05Assume sample…

Q: A survey was conducted that asked 1079people how many books they had read in the past year. Results…

A: Given, Sample size = 1079 Sample mean  = 13.3 Sample standard deviation = 18.9 Since the population…

Q: Help In a survey of 3031 adults aged 57 through 85 years, it was found that 85.7% of them used at…

A: Given: n=3031 pcap=0.857

Q: The annual earnings (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: From the provided information, Sample size (n) = 35 Confidence level = 98%

Q: Find a 95% confidence interval for the difference between full attendance students' Exam 5 score and…

A: We have given data,  Less attendance Full attendance 90 96 90 96 60 100 50 99 69   88…

Q: You are interested in finding a 98% confidence interval for the average commute that non-residential…

A: Given27,27,9,26,9,26,19,18,17,25,24sample size(n)=11

Q: Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a…

A: Margin of error(E)=4%=0.04confidence level=99%

Q: A newspaper provided a "snapshot" illustrating poll results from 1910 professionals who interview…

A: We have given that point estimate = 0.26Margin of error = ±3% 0.03 Sample size (n) = 1910

Q: (c) If the confidence levels were 98% rather than 80%, would the margin of error be larger or…

A: Given Sample size, n=175 Sample mean, x¯=2.94Population sd,σ=0.45

Q: Explain how to find the 95% confidence interval for the mean by hand using the following data set…

A: For the given sample, x¯=59.05, from the excel function, =AVERAGE(J2:J21)s=4.6394, from the excel…

Q: ♦️♦️♦️✅✅❎❎✅♦️♦️✅✅✅✅♦️♦️♦️✅✅✅

A: Part 1 To find the number of human resource professionals who said that body piercings and tattoos…

Q: In a survey of 2417 adults in a recent​ year, 1458 say they have made a New​ Year's resolution.…

A:

Q: the difference P-P2 when x 40, n, = 80, x, = 20, and n, nce in 60. Round the answer to at least…

A: Given : n1 = 80 x1 = 40 n2 = 60 x2 = 20 confidence level,c=0.8

Q: A random sample of 56 fluorescent light bulbs has a mean life of 645 hours and assume that the…

A: The given data is as follows:Sample size, Sample mean, Population standard deviation,

Q: Determine the margin of error for the confidence interval for the proportion: <0.58<p0.821   The…

A: We have given  confidence interval for the proportion: 0.58&lt;p&lt;0.821 LCL =0.58 UCL=0.821…

Q: The data below shows the weight of 11 students taking SMA 2272:    71,81,65,55,48,93,82,73,67,89 and…

A:

Q: Please no written by hand solutions 70 Australian households were randomly selected and surveyed.…

A: Answer:- According to the given information,  n = 70 X = 45  Confidence level = 95% = 0.95  So,…

Q: What is the margin of error for 95% confidence for a sample of size 700 where p = 0.65? A. 0.0455…

A: to find  the margin of error for 95% confidence sample size n =700 p = 0.65

Q: A polling firm called 1,000 likely voters to ask about their political preferences. Of those polled,…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.