Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 2 percentage points and use a confidence level of 90%. Complete parts and (b) below. a. Assume that p and q are unknown. n=1691 (Round up to the nearest integer.) b. Assume that 25% of adults can wiggle their ears. no (Round up to the nearest integer.)

Claim: : P = 0.23; a 0.10; Sample Statistics : P = 0.17₁ n = 100 A.) Find the 2- test static. Select the Correct Choice below and, if necessary, fill in the answer box to Complete Your choice. 2 = ( Round to two decimal places as needed) 0 3.) What is the result of the test Reject or fail to reject? ?

Do men take less time than women to get out of bed in the morning? The 42 men observed averaged 7.6 minutes to get out of bed after the alarm rang. Their standard deviation was 2.2. The 52 women observed averaged 9 minutes and their standard deviation was 2.1 minutes. What can be concluded at the a = :0.01 %3D level of significance?

A. Which one is greater the mean or the median? Which one is better measured of the center the median or the mean? Show work B. Find the mode C. Find the median D. Find the mean (even though we must round to the one decimal place to make computations easy round you’re mean to the nearest minute)

Pls refer to image

Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 90​% confidence that your error is no more than 0.04. The sample should include ___ men and ___ women.

= 12,000 and p = 0.71. A random sample of 902 elements selected from this population gave p 0.61. Find For a population, N the sampling error. Enter the exact answer. sampling error =

Use estimation to select the best response. Do not calculate.Which of the following is more probable? Flipping a coin two times and obtaining at least 2 heads. Flipping a coin five times and obtaining at least 2 heads.     They are equally probable.

Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is  = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and σ = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is μ = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. (a) What is the level of significance? (Enter a number.) State the null and alternate hypotheses. Will you use a left-tailed, right-tailed, or two-tailed test? H0: μ = 4.3 g; H1: μ > 4.3 g; right-tailed H0: μ < 4.3 g; H1: μ = 4.3 g; left-tailed…

Consider sample data with x = 39 and s = 4.Compute the coefficient of variation. Round to two decimal places. ?%