Find the sample size needed to estimate the percentage of adults who can wiggle their ears. Use a margin of error of 2 percentage points and use a confidence level of 90%. Complete parts (a)and (b) below.a. Assume that p and q are unknown.n=1691(Round up to the nearest integer.)b. Assume that 25% of adults can wiggle their ears.ns(Round up to the nearest integer.)View an example Get more help.F280F3QF4nF5MacBook AirCF68.F7F8F9F10Clear allF11+Check answerF12

given data, E= 2%CI=0.90α=1-0.90=0.10for 90% CI, z-critical value:Zc:=Z0.10/2=Z0.05=1.645 [ from…

Answered: Find the sample size needed to estimate…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Assume that a sample is used to estimate a population proportion p. Find the margin of error E that corresponds to the statistics and confidence level. Round the margin of error to four decimal places. 90% confidence; n = 369, x = 133 Type your answer...
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 90% confidence that your error is no more than 0.035. A Click the icon to view the discussion of sample size. The sample should include men and women. (Type whole numbers.)
I need help explaining parts a and b.
Claim: : P = 0.23; a 0.10; Sample Statistics : P = 0.17₁ n = 100 A.) Find the 2- test static. Select the Correct Choice below and, if necessary, fill in the answer box to Complete Your choice. 2 = ( Round to two decimal places as needed) 0 3.) What is the result of the test Reject or fail to reject? ?
Do men take less time than women to get out of bed in the morning? The 42 men observed averaged 7.6 minutes to get out of bed after the alarm rang. Their standard deviation was 2.2. The 52 women observed averaged 9 minutes and their standard deviation was 2.1 minutes. What can be concluded at the a = :0.01 %3D level of significance?
C. Solve for the problem. A population consists of the numbers 2, 4, 5, 9 and 10. Take three numbers as samples from the population. Present the frequency distribution of all the possible samples taken
A. Which one is greater the mean or the median? Which one is better measured of the center the median or the mean? Show work B. Find the mode C. Find the median D. Find the mean (even though we must round to the one decimal place to make computations easy round you’re mean to the nearest minute)
Pls refer to image
Use the expression in the accompanying discussion of sample size to find the size of each sample if you want to estimate the difference between proportions of men and women who own smartphones. Assume that you want 90% confidence that your error is no more than 0.04. The sample should include ___ men and ___ women.
Directions: Read and answer the following questions independently. Show your solution if necessary. 2. If the mean of the sampling distribution is 24.29, what is the mean of the population?
= 12,000 and p = 0.71. A random sample of 902 elements selected from this population gave p 0.61. Find For a population, N the sampling error. Enter the exact answer. sampling error =
Bill Alther is a zoologist who studies Anna's hummingbird (Calypte anna). (Reference: Hummingbirds, K. Long, W. Alther.) Suppose that in a remote part of the Grand Canyon, a random sample of six of these birds was caught, weighed, and released. The weights (in grams) were as follows. 3.7 2.9 3.8 4.2 4.8 3.1 The sample mean is = 3.75 grams. Let x be a random variable representing weights of hummingbirds in this part of the Grand Canyon. We assume that x has a normal distribution and ? = 0.64 gram. Suppose it is known that for the population of all Anna's hummingbirds, the mean weight is ? = 4.30 grams. Do the data indicate that the mean weight of these birds in this part of the Grand Canyon is less than 4.30 grams? Use ? = 0.10. Level of significance = .10 Null and alternate hypotheses. - H0: ? = 4.3 g; H1: ? < 4.3 g; left-tailed Sampling Distribution - The standard normal, since we assume that x has a normal distribution with known ? Compute the z value of the sample test…

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