What is the appropriate MIPS code equivalent to given c-style co int doAdd (int t0, int tl) { return t0+tl*2; } a) sll $al,$al,l add $v0,$a0,$al jr $ra doAdd: b) mul $r1,$rl,2 add $v0,$r0,$rl jr $ra doAdd: c) sll $t1,$t1,1 add $v0,$t0,$t1 jr $ra doAdd: d) doAdd: mul $s1,$sl,2 add $v0,$s0,$s1 jr $ra

C++

I need this code to be with python 3 1. Approach: Non recursive: //include necessary header files#include <iostream>using namespace std;//main functionint main(){    int days,buy_on_this_day ,sell_on_this_day;    //get number of days as input from user    cout<<"Enter number of days: ";    cin>>days;    int stock_price[days];    for(int i=0;i<days;i++)    {   cout<<"Enter stock_price";        cin>>stock_price[i];    }    int i=0;    for(int i=0;i<days-1;i++)    {        //comparing  current price with next day price and finding the  minima        while(i<days-1 && stock_price[i+1]<=stock_price[i])        i++;         if(i==days-1)        break;        buy_on_this_day  =i++;         while(i<days && stock_price[i]>= stock_price[i-1])        i++;        sell_on_this_day =i-1;        cout<<buy_on_this_day <<" : index of the change before  we buy"<<endl;        cout<<sell_on_this_day<<"  :index…

Q1: 1. What is the output of this C code? void main(){ int a = 0, i = 0, b; for (i=0;i< 5; i++){ a++;continue; } cout<<"i="<

C++