Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN: 9780133594140
Author: James Kurose, Keith Ross
Publisher: PEARSON
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Question

What is this programming language?  C or C++

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#include <iostream>
#include <string.h>
using namespace std;
int val (char c)
11 E {
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if (c >= '0' && c <= '9')
return (int)c - '0';
else if (c >= 'A' && c <= 'z')
return (int)c - 'A' + 10;
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else
return (int)c - 'a' + 10;
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int toDeci(char *str, int base)
20 E {
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int len =0;
while(str[len]!= '\0') {len++;}
int power = 1;
int num = e;
int i;
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for (i = len - 1; i >= @; i--)
{
if (val(str[i]) >= base)
{
printf("Invalid Number");
return -1;
}
num +=val(str[i]) * power;
power = power * base;
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return num;
}
int main ()
39 E {
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char numbers[5][18];
cout<<"Enter five numbers in base 14 below\n";
for (int i=0;i<5;i++){
cout<<"Enter number "<<i+1<<" : ";
cin>>numbers[i];
}
cout<<"Number in 14th Base \tCorresponding Decimal Number\n";
for (int i=0;i<5;i++){
cout<<numbers[i]«"\t\t\t"<«toDeci(numbers[i],14)<<endl;
}
return e;
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}
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+ n6 7 00
mmm mm
expand button
Transcribed Image Text:7 #include <iostream> #include <string.h> using namespace std; int val (char c) 11 E { 8 9 10 if (c >= '0' && c <= '9') return (int)c - '0'; else if (c >= 'A' && c <= 'z') return (int)c - 'A' + 10; 12 13 14 15 16 else return (int)c - 'a' + 10; 17 18 int toDeci(char *str, int base) 20 E { 19 int len =0; while(str[len]!= '\0') {len++;} int power = 1; int num = e; int i; 21 22 23 24 25 for (i = len - 1; i >= @; i--) { if (val(str[i]) >= base) { printf("Invalid Number"); return -1; } num +=val(str[i]) * power; power = power * base; 26 27 28 29 30 31 32 33 34 return num; } int main () 39 E { 37 38 char numbers[5][18]; cout<<"Enter five numbers in base 14 below\n"; for (int i=0;i<5;i++){ cout<<"Enter number "<<i+1<<" : "; cin>>numbers[i]; } cout<<"Number in 14th Base \tCorresponding Decimal Number\n"; for (int i=0;i<5;i++){ cout<<numbers[i]«"\t\t\t"<«toDeci(numbers[i],14)<<endl; } return e; 40 41 42 E 43 44 45 46 47 48 49 50 51 } 52 + n6 7 00 mmm mm
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