What does the slope of the fit line in this log-voltage vs. current represent? log voltage 3.5 3 2.5 2 1.5 0.5 -0.5 log voltage vs current of light bulb log voltage = 7.2566 Current - 1.4487 R2 = 0.988 0.1 0.2 0.3 0.4 current O The slope is the resistance of the light bulb The slope is the rate of increase of the voltage at each current O The slope is the reciprocal of the light bulb O The slope is the initial vale of the voltage 0.5 0.6 0.7
What does the slope of the fit line in this log-voltage vs. current represent? log voltage 3.5 3 2.5 2 1.5 0.5 -0.5 log voltage vs current of light bulb log voltage = 7.2566 Current - 1.4487 R2 = 0.988 0.1 0.2 0.3 0.4 current O The slope is the resistance of the light bulb The slope is the rate of increase of the voltage at each current O The slope is the reciprocal of the light bulb O The slope is the initial vale of the voltage 0.5 0.6 0.7
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Transcribed Image Text:What is/are the reasonable steps for linearizing a non-linear plot like this?
Non-linear nature of light bulb Resistance
8
4
6
S
voltage(V)
A
3
0
0
voltage = 0.3497e119.3 Current
R² = 0.9699
0.005
O Both in the list
0.01
None in the list
0.015
Current(A)
0.02
O Determine the model equation based on the trend-line
O Make a semi-log (log of data on one axis) if the model is exponential
0.025
0.03
Transcribed Image Text:What does the slope of the fit line in this log-voltage vs. current represent?
log voltage
3.5
3
2.5
2
1.5
1
0.5
-0.5
log voltage vs current of light bulb
log voltage = 7.2566 Current - 1.4487
R² = 0.988
0.1
0.2
0.3
0,4
current
The slope is the resistance of the light bulb
The slope is the rate of increase of the voltage at each current
The slope is the reciprocal of the light bulb
The slope is the initial vale of the voltage
0.5
0.6
0.7
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