What are the correct intermediate steps of the following data set when it is being sorted with the Insertion sort? [otjr] Select one: O a. [orjt] -- [jrot] -- ljo,rt] -- ljo,rt] O b. [o,tjr] -- ljo,tr] -- ljort] oc. [ojtr] -- [ojr,t] -- ljort) od li, tor] -- ljo,trl -- ljo.rt)

What are the correct intermediate steps of the following data set when it is being sorted with the Insertion sort? [otjr] Select one: O a. [orjt] -- [jrot] -- ljo,rt] -- ljo,rt] O b. [o,tjr] -- ljo,tr] -- ljort] oc. [ojtr] -- [ojr,t] -- ljort) od li, tor] -- ljo,trl -- ljo.rt)

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Language: Python 3 Autocomplete Ready O 1 v import ast 3. Hybrid Sort input() lst %3D 3 lst = ast.literal_eval(lst) 4 Insertion sort is a simple sorting algorithm that builds the final sorted array one item at a time. In each iteration, insertion sort inserts an element into an already sorted list (on left). The position where the item will be inserted is found through linear search. You decided to improve insertion sort by using binary search to find the position p where the new insertion should take place. 6 print(BinaryInsertionSort(lst)) Algorithm BinarylnsertionSort Input/output: takes an integer array a = {a[0], ..., a[n – 1]} of size n begin BinarylnsertionSort for i =1 to n val = a[i] p = BinarySearch(a, val, 0, i – 1) for j = i-1 to p a[j + 1]= a[i] j= j-1 end for a[p] = val i i+1 end for end BinarylnsertionSort Here, val = a[i] is the current value to be inserted at each step i into the already sorted part a[0], ..., ați – 1] of the array a. The binary search along that part…
Language: Python 3 • Autocomplete Ready O 1 v import ast lst = input(O lst = ast.literal_eval(lst) def binarysearch(lst,x,low,high): if low - high x: 10 11 Algorithm BinarylnsertionSort 12 Input/output: takes an integer array a = {a[0], ..., a[n – 1]} of size n 13 begin BinarylnsertionSort return binarysearch (lst, x, mid, high) 14 for i =1 to n val = a[i] p = BinarySearch(a, val, 0, i – 1) for j = i-1 to p alj + 1]= a[j] j= j-1 end for 15 else: 16 return mid 17 18 def BinaryInsertionSort(lst): 19 print (BinaryInsertionSort(lst)) 20 a[p] = val j=i+1 end for end BinarylnsertionSort Here, val = a[i] is the current value to be inserted at each step i into the already sorted part a[0], ..., ați – 1] of the array a. The binary search along that part returns the position p where the val will be inserted. After finding p, the data values in the subsequent positions j = i- 1, ..., p are sequentially moved one position up to i, ..., p+1 so that the value val can be inserted into the proper…
1 v import ast lst = input() lst = ast.literal_eval(lst) 4. Sort Matrix By Row 4 Using Selection Sort, write a function sort_matrix_by_row that takes a matrix and sort the elements in the rows of a Matrix. 6 print(sort_matrix_by_row(lst)) >>> sort_matrix_by_row([[5, 8, 1], [6, 7, 3], [5, 4, 9]]) [[1, 5, 8], [3, 6, 7], [4, 5, 9]] >>> sort_matrix_by_row([['chair','table', 'house'], ['square', 'rectangle', 'triangle'],['motor cycle', 'car', 'truck']]) [['chair', 'house', 'table'], ['rectangle', 'square', 'triangle'], ['car', 'motor cycle', 'truck']]
Your task is sorting the given list by dictionary order, sortingoperation must be realized using the bubble sort algorithm. Additionally,this list implementation should be written using a two-dimensional char ar-ray.Bubble Sort Algorithm1 function swap ( a , b)2 // F i l l own your own !3 end function45 function compare ( a , b)6 // Compare f unc t i on should be implemented7 // to r e a l i z e the s o r t i n g c r i t e r i a .8 // For example , e l ement s in a are s t r i n g s and9 // the y are to be s o r t e d in d i c t i o n a r y order .10 // strcmp f unc t i on can be used in p l a c e11 // of compare f unc t i on .12 end function1314 function bubbl e s o r t ( a , n)15 while n != 016 high = 017 for i=0 to n=2 incremented by 118 i f compare ( a [ i ] , a [ i +1]) > 0 then19 swap ( a [ i ] , a [ i +1])20 high = i+121 end i f22 end for23 n = high24 end while25 end function1
Python help----- Using HASH sorting algothrim create only one function def sortstring(filename): that takes in a file which has a bunch of sentences, each line of sentence consting of different length. Sort the setences from the lower length senteces to the highest length sentence. Print it after ( DON'T USE ANY SORTING BULT-IN FUNCTION ). Note: Keep note of time complexity as it should be able to run few 10,000 lines of sentences in few seconds.
def sort and_pop(x: list, i: int) -> list: x.sort() return x.pop(i) # Dan's code lst = [23, 17, 3, 13, 11, 5, 7, 2, 19, 1] lst = sort_and_pop(lst, 5) lst = sort_and_pop(lst, 2) II I| || If you run this code, you'll find that it produces an error. Surprise! According to the type contract, Dan's Code should work. But it doesn't, because the function type contract has faulty type annotations. Correct the function type contract so that it's clear from the type contract that Dan's code will not work. (Dan's Code will and should remain an incorrect use of the function!) TODO: Write a new type contract"" "
On the following groups, track the insertion sort passes:i) {H, K, M, N, P} ii) {P, N, M, K, H}Regarding the comparisons made, evaluate their work.
illustrates the working of selection sort. The procedureFIND_MINIMUM (L,i,n) selects the minimum element from the array L[i:n]and returns the position index of the minimum element to procedureSELECTION_SORT. The for loop in the SELECTION_SORT procedurerepresents the (n-1) passes needed to sort the array L[1:n] in the ascendingorder. Function swap swaps the elements input into it.
Recamán's sequence def recaman_item(n):Compute and return the n:th term of the Recamán's sequence. See the linked definition for this sequence on Wolfram Mathworld. Note how the definition for the current element in this sequence depends on whether some particular number can be found in the previously generated prefix of the sequence. To allow your function to execute in a sure and speedy fashion even for millions of elements, you should use a set to keep track of which elements are already part of the prefix of the sequence generated so far. This way you can generate each element in constant time, instead of having to iterate through the entire previously generated list the way some "Shlemiel" might approach this problem. n Expected result 1 1 8 12 13 23 57 87 395743 258330 The previous version of this problem, simply called recaman in the very first versions of this problem collection,…
Sort-by-Length Write a function sort_by_length(words:List[str]) -> List[str] that returns a list of words, sorted by the length of each word and if some words have the same length, sort them alphabetically. For example, sort_by_length(['this', 'is', 'a', 'test', 'for', 'sorting', 'by', 'length']) == ['a', 'by You can see that the given list is sorted by the length of each word. The shortest word 'a' is in the first position. The by and is have the same length but b comes before i. How do you implement this function? Here are some steps you can follow: 1. Start with an empty list length_word_tuples 2. For each word, create a tuple where its first element is the length of the word and the second argument is the word itself e.g. (4, 'this'). Append the tuple into length_word_tuples. 3. Sort the list length_word_tuples using sorted() function. What is the type of each element of length_word_tuples? How is this different from calling sorted (words)? 4. Create another empty list called ans.…
Apply Selection Sort on the following list of elements: 16, 23, 19, 6, 20, 10, 34, 54
Is it possible to implement insertion sort?