Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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![**Consider the following list:**
`int list[] = {14, 18, 29, 35, 44, 49, 55, 58, 66, 71, 75, 80, 89, 95, 98}`
When performing a binary search for 75, after the first comparison, the search is restricted to ____.
- ⭕ list[8]...list[14]
- ⭕ list[5]...list[11]
- ⭕ list[0]...list[7]
- ⭕ list[0]...list[6]
---
**Explanation of the Binary Search Process:**
Binary search is an efficient algorithm for finding a target value within a sorted array. It works by repeatedly dividing the portion of the array in which the target value could reside in half until the target value is found or the search space is exhausted.
**Steps in this Case:**
1. **Initial Array:**
The given list is: {14, 18, 29, 35, 44, 49, 55, 58, 66, 71, 75, 80, 89, 95, 98}
2. **Find the Middle Element:**
The middle index of a list of 15 elements is `7` (using zero-based index), and the middle value is `58`.
3. **Comparison with Target (75):**
Since 75 is greater than 58, the search is restricted to the right half of the list.
4. **Restricted Search Space:**
Now the search will proceed on the subarray: {66, 71, 75, 80, 89, 95, 98}.
Therefore, after the first comparison, the search is restricted to list[8]...list[14].](https://content.bartleby.com/qna-images/question/e729a476-2c21-47cf-8145-b09785d3a477/d7bd7325-30a0-4ffc-8e37-98c99f150cfb/clp8dj_processed.jpeg)
Transcribed Image Text:**Consider the following list:**
`int list[] = {14, 18, 29, 35, 44, 49, 55, 58, 66, 71, 75, 80, 89, 95, 98}`
When performing a binary search for 75, after the first comparison, the search is restricted to ____.
- ⭕ list[8]...list[14]
- ⭕ list[5]...list[11]
- ⭕ list[0]...list[7]
- ⭕ list[0]...list[6]
---
**Explanation of the Binary Search Process:**
Binary search is an efficient algorithm for finding a target value within a sorted array. It works by repeatedly dividing the portion of the array in which the target value could reside in half until the target value is found or the search space is exhausted.
**Steps in this Case:**
1. **Initial Array:**
The given list is: {14, 18, 29, 35, 44, 49, 55, 58, 66, 71, 75, 80, 89, 95, 98}
2. **Find the Middle Element:**
The middle index of a list of 15 elements is `7` (using zero-based index), and the middle value is `58`.
3. **Comparison with Target (75):**
Since 75 is greater than 58, the search is restricted to the right half of the list.
4. **Restricted Search Space:**
Now the search will proceed on the subarray: {66, 71, 75, 80, 89, 95, 98}.
Therefore, after the first comparison, the search is restricted to list[8]...list[14].
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