A crest vertical curves joining a +3% and -4% grade is to be designed for 90 km/h. If the tangents intersect at station 3+400,00 at an elevation of 76,00 m, determine the stations and elevations of the BVC (beginning of the vertical curve) and EVC (end of the vertical curve). Also calculate the elevations of intermediate points on the curve at the whole stations every 40m.

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: An equal-tangent vertical curve is to be constructed between grades of -3% and +2% (travelling left…

A: Given:- Downgrade of curve, g1 = -3% Upgrade of curve, g2 = +2% Station of PVI = 4 + 550.000…

Q: compound curve has a central angle of 40deg. and radius 280m for the first curve. The second curve…

A: Given data,  Central angle for 1st curve = 40° Central angle of 2nd curve = 28° Radius of 1st curve…

Q: A -6% grade meets a 9% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m. and…

A: Introduction : lowest point on the curve: On a graph, the maximum and minimum points are located…

Q: 23.15 A +4% grade intersects a -3% grade at station 3+ 000m at elevation 566.98 m. Compute the…

A: PVCSTATION=PVISTA-L2PVCsta=3000-6002=2+700PVCELV=PVIELV-g1L2PVCelv=566.98-0.04×6002PVCelv=554.98m

Q: 3.)  A -4% grade meets a 7% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m.…

A: Downward gradient=-4% Upward gradient=7% Elevation=150 m L1=70 m, L2=50 m.

Q: B-Unequal-Tangent Parabolic (Vertical) Curve: Example: A grade g1 of -2% intersects g2 of +1.6% at a…

A: Solution: Point A STA 85 + 00: Elev. = 743.24+2(2) = 747.24' Point B STA 90 + 00: Elev. =…

Q: angent grades of +2 on of 152 m above th th of the passing sig of the curve. (c) Co

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Q: PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3%   The…

A: Data given Sta PI = 18+00 Elevation of PI = 300  L = 20 stations G1 = +2% G2 = -3% To find: -…

Q: A grade of -5% grade intersects a grade of 0%. P.C. has a STATION of 10 + 110.00 which has an…

A: Given that   Sag vertical curve   g1 = -5%   g2 = 0   A = G1-G2   A = -5   PC station = (10+110)…

Q: Two straights, AR having gradient falling to the right at 9V:6H and RT having gradient rising to the…

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Q: 8, Horizontal Alignment Design - A horizontal curve has a deflection angle of 60 degree and a radius…

A: Radius of curve (R) = 300m Deflection angle (∆ or α) = 60°If the length of the curve is equal to…

Q: vertical parabolic curve of length 180m has he following specifications. The point of teraction of…

A:

Q: A 9% grade meets a 5% grade at station 2 + 270 of elevation 150 m. The lengths are L1 = 80 m. and L2…

A: Given: The grade g1 is 9%. The grade g2 is 5%. The station PVI is 2 + 270. The elevation of PVI is…

Q: A +3% grade intersects a -2% grade at STA 4+350 meter at an elevation of 190.50 meter. Given that a…

A: The backward grade, g1 = +3%the forward grade, g2 = -2%The Station of point of vertical…

Q: Vertical summit curve has tangent grades of +1.5% and - 1.5% intersecting at station 4+000 at an…

A: Given- n1=+1.5%n2=-1.5%L=182

Q: NEED ASAP A summit curve has tangents intersects at Pl at station 14+750 with elevation of 76.30m.…

A: PVCSTATION=PVISTA-L2PVCsta=14750-3002=14+600PVCELV=PVIELV-g1L2PVCelv=76.3-0.034×3002PVCelv=71.2

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

A:

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: ngent vertical curve c -3.2% and a -1.1 % g e PVI is at station 10 d elevation 950 ft an T is at…

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Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

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Q: A horizontal curve with spiral is being designed for a new two-lane highway (3.6-m anes and 2%…

A:

Q: A +4% grade line intersects a -2 % grade line at station 6+800, where the elevation is 642.40 m. as…

A: When a route changes direction from right to left or its alignment changes from up to down, curves…

Q: A symmetrical Crest curve have two vertical grades intersects at station (12+80) (1 station = 100…

A: Given values, Symmetrical crest curve with vertical grades, g1= +2%, g2 = -2% Point of intersection…

Q: VERTICAL PARABOLIC CURVE IS TO CONNECT A BACK TANGENT OF -2% AND A FORWARD TANGENT OF 3%. THE CHANGE…

A:

Q: 9. A-6% grade meets a 9% grade at station 2 + 185 of elevation 150 m. The lengths are Li 70 m. and…

A: Consider the given data g1=-6%,  g2=+9%A=9+6=15%L1=70 m,    L2=50 mPVI elevation=150 m Calculate the…

Q: A forward tangent of +6% was designed to intersect a back tangent of -3% at a proposed underpass…

A:

Q: 23.1 A 1,500-ft vertical curve is to be used for joining a +3.0% grade line and a-4.0% grade line.…

A: The length of curve, L= 1500 ftThe grade of upgrade, g1 = +3%The grade of downgrade, g2 = -4%The…

Q: vertical parabolic curve is to be used as a grade-separation structure. The curve is 231 m long and…

A:

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A: Given: Sight Distance= 120 m  Grade lines intersection   Station = 9+000 Elevation = 160.50 m…

Q: A vertical parabolic curve is to be used as a grade-separation structure. The curve is 242 m long…

A: Here's the calculation: First, we need to find the parabolic constant (K) using the formula: K = (G2…

Q: A vertical parbolic curve was design in order to have a clear sight distance of 120 m . The grade…

A: sing relation for SSDSSD=vt+v22gf±Gf=0.35G=0.05t=2.5sec

Q: A simple curve having a degree of curve equal to 3.8-degree has central angle of 55.5-degree. It is…

A: ∆(deflection angle) = 55.5o S (shift of curve) = 6.8 m S = L224R Station of PI = 4 + 657.89

Q: 26.10 A grade of +1.5% intersects a grade of -2.5% at station of 1 + 080 of elevation 68.94 m. if…

A: Given Data:g1=1.5%g2=-2.5%station=1+080Elevation=68.94m

Q: A -6% grade is followed by a 2% grade intersecting at Sta. 15+750, with an elevation of 372.25 m.…

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Q: curve is 10°. The curve has 7 intermediate stations between P.C. (10 + 300m) and P.T. After laying…

A: Given:- 5m full station curve=10 degree 7 intermediate stations  P.C.(10+300m) To find:- Compute all…

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.