A crest vertical curves joining a +3% and -4% grade is to be designed for 90 km/h. If the tangents intersect at station 3+400,00 at an elevation of 76,00 m, determine the stations and elevations of the BVC (beginning of the vertical curve) and EVC (end of the vertical curve). Also calculate the elevations of intermediate points on the curve at the whole stations every 40m.

Q: An old equal-tangent crest vertical curve was designed with a PVI at station 117+45 and elevation of…

A: An equal tangent crest vertical curve is as below The point PVC is called as the initial tangent…

Q: compound curve has a central angle of 40deg. and radius 280m for the first curve. The second curve…

A: Given data,  Central angle for 1st curve = 40° Central angle of 2nd curve = 28° Radius of 1st curve…

Q: A -6% grade meets a 9% grade at station 2 + 185 of elevation 150 m. The lengths are L1 = 70 m. and…

A: Introduction : lowest point on the curve: On a graph, the maximum and minimum points are located…

Q: PI sta = 18+00, PI elev = 300.00, L = 20 stations, incoming grade = +2%, outgoing grade = -3%   The…

A: Data given Sta PI = 18+00 Elevation of PI = 300  L = 20 stations G1 = +2% G2 = -3% To find: -…

Q: 8, Horizontal Alignment Design - A horizontal curve has a deflection angle of 60 degree and a radius…

A: Radius of curve (R) = 300m Deflection angle (∆ or α) = 60°If the length of the curve is equal to…

Q: An equal tangent sag equal tangent verticle curve (with a negative initial and a positive final…

A:

Q: Vertical summit curve has tangent grades of +1.5% and - 1.5% intersecting at station 4+000 at an…

A: Given- n1=+1.5%n2=-1.5%L=182

Q: NEED ASAP A summit curve has tangents intersects at Pl at station 14+750 with elevation of 76.30m.…

A: PVCSTATION=PVISTA-L2PVCsta=14750-3002=14+600PVCELV=PVIELV-g1L2PVCelv=76.3-0.034×3002PVCelv=71.2

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

A:

Q: An equal-tangent sag curve of length 920ft needs to be designed for 55 mph to connect an initial…

A: Given:- The length of the sag curve = 920 ft The design speed = 55 mph The initial downgrade = 5%…

Q: The elevation of PT is at elevation 454.50m while the lowest point on the curve is located 40m from…

A:

Q: A horizontal curve with spiral is being designed for a new two-lane highway (3.6-m anes and 2%…

A:

Q: A symmetrical Crest curve have two vertical grades intersects at station (12+80) (1 station = 100…

A: Given values, Symmetrical crest curve with vertical grades, g1= +2%, g2 = -2% Point of intersection…

Q: 9. A-6% grade meets a 9% grade at station 2 + 185 of elevation 150 m. The lengths are Li 70 m. and…

A: Consider the given data g1=-6%,  g2=+9%A=9+6=15%L1=70 m,    L2=50 mPVI elevation=150 m Calculate the…

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A: Given: Sight Distance= 120 m  Grade lines intersection   Station = 9+000 Elevation = 160.50 m…

Q: A vertical parbolic curve was design in order to have a clear sight distance of 120 m . The grade…

A: sing relation for SSDSSD=vt+v22gf±Gf=0.35G=0.05t=2.5sec

Q: A simple curve having a degree of curve equal to 3.8-degree has central angle of 55.5-degree. It is…

A: ∆(deflection angle) = 55.5o S (shift of curve) = 6.8 m S = L224R Station of PI = 4 + 657.89

Q: You are required to set up a vertical curve for a highway alignment. Gradient of the backward and…

A: As per our guidelines we can solve one question only or the first three sub-parts only. If you need…

Q: 3. If a vertical curve is introduced between an upgrade of 0.5 in 100 followed by a down grade of…

A: The given data is: h1=0.5 h2=0.9 Offset, S=30 m N=h1+h2 N=0.5+0.9=1.4 %

Q: A 4.5% grade intersects a -1% grade at STA 5+180 at an elevation of 195m. A vertical curve of length…

A: Given: The length of vertical curve is 120 m. Here: PVC Station=PVI Station- Length of vertical…

Q: An equal-tangent vertical curve connects a +1.5% initial grade and a -3% final grade. The PVT is at…

A: Following are the given information.Initial grade, Final grade, Station of PVT Elevation of PVT…

Q: A 600 ft equal tangent vertical The initial grade is -3.5% and the final grade is +0.5%. Determine…

A: L=600ft

Q: A symmetrical parabolic commit curve connects two grades of +6% and -4%. It is to pass a point "A"…

A:

Q: roads with grades of +4.5% and -3% meet at station 15 + 100 at an elevation of 72.344 m. If the…

A:

Q: Design a vertical curve connecting PVI₁ (station = 4+980, Elevation = 198 m), PVI₂ (station = 5+990,…

A: PVI₁ (station = 4+980, Elevation = 198 m) PVI₂ (station = 5+990, Elevation = 163 m) and PVI₃…

Q: Q3/ Given the following vertical curve data: pvl at 19+00,L-500 ft g1=+2.5%, g2= -1% and elevation…

A: Given:- The stationing of point PVI = (19+00) The length of the curve = 500 ft The initial grade of…

Q: Questions 5. a) A vertical crest curve has an approach grade +3% and a departure grade -2%. The…

A: Given : Approach grade = +3% and departure grade = -2%  Intersection point level is 100m (AHD)]…

Q: A VERTICAL PARBOLIC CURVE WAS DESIGN IN ORDER TO HAVE A CLEAR SIGHT DISTANCE OF 120 M. THE GRADE…

A:

Q: A -6% grade and a +2% grade intersect at STA 12 + 200 whose elevation is at 25.632 m. The two grades…

A:

Q: 2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade…

A:

Q: A crest vertical curve joining a + 3 percent and – 4 percent grade is to be designed for 75 mph. If…

A:

Curve setting

A curve is a turn that is provided horizontally or vertically in the design of highways, railways, and runways. A curve connects two straight lines that are separated by the deflection angle. It helps to change the direction and alignment of the highways, railway tracks, and runways. Therefore, the gradual change in their alignment is made by using a curve to provide comfort to the passengers and this also provides an easy turn to change the direction of the moving vehicle.