Questions 5. a) A vertical crest curve has an approach grade +3% and a departure grade -2%. The Intersection Point (IP) level is 100m Australian Height Datum (AHD), on Chainage 1000 m. It is proposed to use a curve 550m long. Calculate: i) Chainage and Level at TP1 ii) Chainage and Level at TP2. iii) Chainage and level at the apex point.

Questions 5. a) A vertical crest curve has an approach grade +3% and a departure grade -2%. The Intersection Point (IP) level is 100m Australian Height Datum (AHD), on Chainage 1000 m. It is proposed to use a curve 550m long. Calculate: i) Chainage and Level at TP1 ii) Chainage and Level at TP2. iii) Chainage and level at the apex point.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Using a well annotated diagram, present the five point permissible approximations or assumptions used for the computations related to vertical curve design and setting out. A 100 metre vertical curve is to connect a downgrade of 1.75% to an upgrade of 1.25%. If the level of the intersection point of the two grades is 150m, calculate the curve levels at 20m intervals, showing the second difference check on the computation.
SHOW COMPLETE SOLUTION AND/OR ILLUSTRATIONS
2. A vertical parbolic curve was design in order to have a clear sight distance of 120 m. The grade lines intersect at Sta 9+000 at elev 160.50 . The curve was design such that when the height of the drivers eye is 1.50 m above the payment it would just see an object whose height is 0.10m above the pavement. Determine the max speed that a car could travel grade of 5% and a downgrade of -3%.
1. A vertical parabolic summit curve was designed in order to have a clear sight distance of 120m. The grade lines intersect a Station 9 + 000 at elevation 160.50m. The curve was so designed such that when the height of the driver's eye to 1.50m above the pavement would just see an object whose height is 0.10m above the pavement. Determine the max. speed that a car could travel along this curve. The grade lines has an upward grade of 5% and a downward grade of -3%.
Determine the station at the end of the tangent runout after the end of the curve (the point at which the road returns to normal crown). The 70km/h, four lane asphalt road has a design radius of 500m, design emax of 4%, 3.10m lane width. The curve starts at 1+505.231 km, and has a curve length of 550m. Input your answer in the format #+###.# km (including units).
Design the curve, of An equal tangent vertical curve is to be constructed between grades of -2.0% (initial) and 1.0% (final). The PVI is at station 11 + 000.000 and at elevation 420 m. Due to a street crossing the roadway, the elevation of the roadway at station 11 + 071.000 must be at 421.5 m. GIVEN DIMENSIONS ON THE ATTACHED PICTURE
Summit curve
A rising gradient AB and a falling gradient BC are to be connected by a vertical curve. Based on the data given in Table Q1, design the curve at 20 metres intervals. Table Q1 (Units are in metres) First Grade (± %) Second Grade (+ %) Sighting Distance (SSD) Driver's eye (h₁) Object height (h₂) 4.2 -1.8 145 1.05 0.3 F G RL of highest/lowest pt Chainage of highest/lowest pt| H 39.171 4048.600 K
Q6. To help improve the safety of at-grade intersection of two roads, the intersection is being redesigned so that the E-W road will pass underneath the N-S road. Currently the vertical alignment of the E-W road consists of a crest vertical curve joining a 4% upgrade to a 3% downgrade. The existing vertical curve is 138 m long, the PVC of this curve is at station 14+47, and the elevation of the PVC is 477 m. The centerline of the N-S road is at station 15+45. Your job is to find the shortest vertical curve that provides 6.0 m of clearance between the new E-W road and the N-S road.
A -3% grade meets a +5% grade near an underpass. In order to maintain the minimum clearance allowed under the bridge and at the same time introduce a vertical transition curve in the grade line, it is necessary to use a curve that lies 200 m on one side of the vertex of the straight grade and 100 m on the other. The station of PC is 10 + 000 and its elevation is 228 m. Determine the stationing of the lowest point of the curve. A 10+211 B. 10+200 C. 10+106 D. 10+207
A horizontal curve with a degree of curvature of 6° is required between the two tangents AB and BC shown below. The length of line AB is 245 m and line BC is 195 m. This road project starts at point A, which is located at station 5+000. Determine the stations of the point of intersection and the end of the curve. Show all your work