Answered: we now have: Step 1: Fast, reversible…

we now have: Step 1: Fast, reversible HA = H+ + A- Step 2: Fast, reversible X + H+ = HX+ Step 3: Slow HX+ = productsrate= k3 k2/k-2 [X][HX+] Does the current rate law contain an intermediate?

Chemistry

9th Edition

ISBN:9781133611097

Author:Steven S. Zumdahl

Publisher:Steven S. Zumdahl

Chapter12: Chemical Kinetics

Section: Chapter Questions

Problem 11RQ: Why does a catalyst increase the rate of a reaction? What is the difference between a homogeneous...

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Question

we now have:

Step 1: Fast, reversible HA = H+ + A-

Step 2: Fast, reversible X + H+ = HX+

Step 3: Slow HX+ = products
rate= k3 k2/k-2 [X][HX+]

Does the current rate law contain an intermediate?

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