We have the following information about the random variables X and Y: -1.5, o = 0.25, of 1. X μχ = 1, με zv = Calculate the variance of Z - 3X + 5Y, a) when the coefficient of correlation is p(X, Y) = 0.46: 0²77 41.05 = X b) when X and Y are independent random variables: o² =[

We have the following information about the random variables X and Y: 0.25, o μχ = 1, με = -1.5, o X = = Calculate the variance of Z = 3X + 5Y, = a) when the coefficient of correlation is p(X, Y) = 0.46: 0²2 27.71 X : 1. b) when X and Y are independent random variables: 0²/2 27.75

How would I solve this assuming the population variances are equal?

The length (in mm) of a spring subjected to a force FNewtons is of the form L = a + BF+ ɛ, where ɛ is assumed normally distributed with mean 0, variance o2. Given the sample statisticsn=D13, E F;= 138, E L; = 577, SEL = -43, SEF= 1735, estimate the expected length of the spring when a force of 11.2 Newtons is applied. (Give your answer correct to 2 decimal places.) Answer: Ti Check 江一 prime viden Type here to search 19 hp ins prt fu f12 f8 f9 f10 f7 f5 f6 『米 " JOI JDI & 6 7 8 5 96 %24 3