We give: AB: adiabatic trigger such as VB = 2 VA AC: isothermal compression PA =1bar=105 Pa , VA = 10^-2 m3 Gas temperature at point A: TA= 300 Kelvin Perfect gas constant: R = 8,31 J.mol-1.K-1 Molar thermal capacity at constant pressure:Cp = 29 J.mol-1.K-1 Calorific capacity ratio of this gas: Cp/Cv = 1,40 4 – Calculate the amount of QBC heat and WBC work received by the system for the transformation that changes the system from state B to state C. 5 – a – Why is the UCA internal energy variation of the gas zero during the CA transformation? b – Apply the first principle to the ABCA cycle and deduce the WAB work received by the gas during the adiabatic relaxation AB. c – Interpret the WAB sign.

We give: AB: adiabatic trigger such as VB = 2 VA AC: isothermal compression PA =1bar=105 Pa , VA = 10^-2 m3 Gas temperature at point A: TA= 300 Kelvin Perfect gas constant: R = 8,31 J.mol-1.K-1 Molar thermal capacity at constant pressure:Cp = 29 J.mol-1.K-1 Calorific capacity ratio of this gas: Cp/Cv = 1,40 4 – Calculate the amount of QBC heat and WBC work received by the system for the transformation that changes the system from state B to state C. 5 – a – Why is the UCA internal energy variation of the gas zero during the CA transformation? b – Apply the first principle to the ABCA cycle and deduce the WAB work received by the gas during the adiabatic relaxation AB. c – Interpret the WAB sign.

Refrigeration and Air Conditioning Technology (MindTap Course List)

8th Edition

ISBN:9781305578296

Author:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Publisher:John Tomczyk, Eugene Silberstein, Bill Whitman, Bill Johnson

Chapter29: Troubleshooting And Typical Operating Conditions For Commercial refrigeration

Section: Chapter Questions

Problem 16RQ

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