We consider a part of an electrical circuit represented in the figure below. The direction of the current flowing through lamp L1 is indicated in the figure, and the intensities of the currents flowing through the lamps L3 and L4 are given respectively. However, no information is given for the currents passing through the lamps L2, Ls and L6. The ammeter A reads 0.5 A. The following voltages are given: UAB = 5 V and UAc = 4 V. B I6 L6 I2 Is L1 A L4 L3 I3 = 0.2 A 14 =0.15 A 1) Show that UBc = - 1 V. 2) Deduce the direction of the current in branch BC. 3) Indicate, on the figure, the direction of the currents in all the branches.

Delmar's Standard Textbook Of Electricity
7th Edition
ISBN:9781337900348
Author:Stephen L. Herman
Publisher:Stephen L. Herman
Chapter18: Resistive-inductive Parallel Circuits
Section: Chapter Questions
Problem 1PA: Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter...
icon
Related questions
Question
AGENDA :
We consider a part of an electrical circuit represented in the figure below. The direction of
the current flowing through lamp L1 is indicated in the figure, and the intensities of the
currents flowing through the lamps L3 and L4 are given respectively. However, no
information is given for the currents passing through the lamps L2, Ls and L6.
The ammeter A reads 0.5 A.
The following voltages are given: UAB = 5 V and UAC = 4 V.
%3D
B
I6
L6
I2
Is
Li
A
A
L4
L3
I3 = 0.2 A
I4 = 0.15 A
1) Show that UBC = - 1 V.
2) Deduce the direction of the current in branch BC.
3) Indicate, on the figure, the direction of the currents in all the branches.
4) Explain why I1 = 0.5 A.
5) Determine the intensities I2, Is and I6.
6) Determine the number of electrons passing through L6 in one minute.
Transcribed Image Text:AGENDA : We consider a part of an electrical circuit represented in the figure below. The direction of the current flowing through lamp L1 is indicated in the figure, and the intensities of the currents flowing through the lamps L3 and L4 are given respectively. However, no information is given for the currents passing through the lamps L2, Ls and L6. The ammeter A reads 0.5 A. The following voltages are given: UAB = 5 V and UAC = 4 V. %3D B I6 L6 I2 Is Li A A L4 L3 I3 = 0.2 A I4 = 0.15 A 1) Show that UBC = - 1 V. 2) Deduce the direction of the current in branch BC. 3) Indicate, on the figure, the direction of the currents in all the branches. 4) Explain why I1 = 0.5 A. 5) Determine the intensities I2, Is and I6. 6) Determine the number of electrons passing through L6 in one minute.
Expert Solution
steps

Step by step

Solved in 4 steps with 3 images

Blurred answer
Knowledge Booster
Solar cell
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Delmar's Standard Textbook Of Electricity
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Electricity for Refrigeration, Heating, and Air C…
Electricity for Refrigeration, Heating, and Air C…
Mechanical Engineering
ISBN:
9781337399128
Author:
Russell E. Smith
Publisher:
Cengage Learning