We are trying to estimate the average lifespan of all Neanderthal humans who lived 100,000 years ago. We collect a sample of 56 skeletons from caves and construct a 95% confidence interval for their lifespans. Which of the following most likely explains why this interval does not include the true average lifespan: OA. There is ongoing debate about how not all human beings present in the world today evolved from Neanderthals O B. The true population mean value of Neanderthal lifespans is neither known, nor likely to be the best measure of central tendency OC. Bones buries in caves are not representative of all humans of that time since they are more likely survive than bones buried elsewhere OD. The lifespans of Neanderthal humans likely did not follow a normal distribution but was likely skewed since many Neanderthal children died in infancy

Millionaires. Professor Thomas Stanley of Georgia State University has surveyed millionaires since 1973. Among other information, Professor Stanley obtains estimates for the mean age, µ, of all U.S. millionaires. Suppose that one year’s study involved a simple random sample of 36 U.S. millionaires whose mean age was 58.53 years with a sample standarddeviation of 13.36 years. a. If, for next year’s study, a confidence interval for µ is to have a margin of error of 2 years and a confidence level of 95%, determine the required sample size.b. Why did you use the sample standard deviation, s = 13.36, in place of σ in your solution to part (a)? Why is it permissible to do so?

A simple random sample of 1000 people age 18 or over is taken in a large town. It turns out that 189 people in the sample are newspaper readers. Calculate a 95%-confidence interval for the percentage of people (age 18 and over) in that town who read newspapers.

A researcher is attempting to calculate a 95% confidence interval for the mean average wingspan of Statsian Swallows in a particular rainforest. They take a sample and find that of the 16 swallows surveyed, the mean average was 3.14 inches and the standard deviation was 0.2 inches. What is the 95% confidence interval for this sample?

In a survey of 1798 US adults, 1365 said they had paid a bill online within the past year.  What is the LOWER endpoint of a 90% confidence interval for the population proportion?  What is the UPPER endpoint of a 90% confidence interval for the population proportion?

You measure 47 randomly selected textbooks' weights, and find they have a mean weight of 80 ounces. Assume the population standard deviation is 4.1 ounces. Based on this, construct a 99% confidence interval for the true population mean textbook weight. Give your answers as decimals, to two places

which of the following sample data: sample size= 100 sample mean= 340z/hr sample variance= 90z/ hr construct a 98% confidence interval  for μ. the population mean is what?

create a 90% confidence interval for the following data:  x = 25 n = 100

In the construction of an 88% Confidence Interval for a population mean u, a has the value of

Out of a sample of 760 people, 367 own their homes. Construct a 95% confidence interval for the population mean of people in the world that own their homes. A CL