A national air traffic control system handled an average of 47,189 flights during 29 randomly selected days in a recent year. The standard deviation for this sample is 6,351 flights per day. what is the 99% confidence interval ?

Q: In a survey, 10 people were asked how much they spent on their child's last birthday gift. The…

A: Here we need to construct an 80% CI for the mean amount of money spent on child's last birthday…

Q: A random sample of 25 statistics students was asked: "Have you smoked a cigarette in the past week?"…

A: From the provided information, Sample size (n) = 25 Six students reported smoking within the past…

Q: When Mendel conducted his famous genetics experiment with peas, one sample of offspring consisted of…

A: Obtain the 95% confidence interval estimate of the percentage of yellow peas. The 95% confidence…

Q: According to a Harris Interactive survey of 2401 adults conducted in April 2009, 25% of adults do…

A:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: It is given that, x is 311 and n is 400.

Q: knowing

A: Given: Total number of drivers = 383 Drivers who buckle up = 297 Proportion of drivers, p =…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: What is the difference between commuting patterns for students and professors. 11 students and 14…

A:

Q: In a survey, 20 people were asked how much they spent on their child's last birthday gift. The…

A: The random variable X is the amount people spent on their child's last birthday gift The sample size…

Q: Out of 400 people sampled, 32 had kids. Based on this, construct a 95% confidence interval for the…

A: Solution: Let X be the number of people had kids and n be the sample number of people. From the…

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Sample taken for ages 19 to 25 2253 men and 2629 women random sample In which 986 men and 923 women…

Q: In a survey of 1005 adults 526 stated construct a 95% confidence interval

A:

Q: In a survey of 3185 adults, 1455 say they have started paying bills online in the last year.…

A:

Q: Out of 200 people sampled, 42 had kids. Based on this, construct a 95% confidence interval for the…

A: For 95% confidence intervalα=1-CI=1-0.95=0.05So, zα2=z0.052=z0.025=1.96

Q: In a survey, 45 people were asked how much they spent on their last partners birthday gift. The…

A: Given information- Sample size, n = 45 Significance level, α = 0.10 Sample mean, x-bar = $90 Sample…

Q: Of 127 randomly selected adults, 31 were found to have high blood pressure. Construct a 95%…

A: Given that, Of 127 randomly selected adults, 31 were found to have high blood pressure.  X = 31 N =…

Q: Out of 180 randomly selected adults in the United States who were surveyed, 81 exercise on a regular…

A:

Q: sample of 35 students was taken from the local university. These students spent an average of $180…

A:

Q: In a survey of 1037 US adults ages 65 and over, 643 were concerned about getting the flu. A 99%…

A: Given,n=1037x=643p^=xnp^=6431037=0.6201-p^=1-0.620=0.380α=1-0.99=0.01α2=0.005Z0.005=2.58    (from…

Q: In a survey of 2255 randomly selected US adults (age 18 or older), 1787 of them use the Internet…

A: We want to calculate the 90% confidence interval for each of the following proportions

Q: In a survey of 3260​ adults, 1456 say they have started paying bills online in the last year.…

A: Givenn=3260x=1456p^=xn=14563260=0.4466

Q: Construct a 95% confidence interval for the ,ean number of hours of watching streaming videos…

A: given: mean=18.5       standard deviation = 3.2 we need to construct 95% CI for mean number of hours

Q: A musicologist is currently writing a report about pop songs in the late 2010s. As a part of her…

A: Givensample size(n)=222Mean(x)=3.05standard deviation(σ)=0.3

Q: Out of 300 people sampled, 171 had kids. Based on this, construct a 95% confidence interval for the…

A:

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A: Required conditions: n1>30 n2>30 n1*p1^>=10 n1*(1-p1^)>=10 n2*p2>=10 n2*p2^>=10

Q: A recent study showed that among 725 randomly selected subjects who completed 4 years of college,…

A: We have given that,  Favorable cases (X) = 139 and Sample size    (n) = 725 Then,  We will find 95%…

Q: A sample of 3048 randomly chosen people found that 341 of them were left-handed. Construct a 99%…

A: Sample proportion=p^=xn=3413048Critical value for 99% confidence interval is=z=2.576n=sample…

Q: A student read that a 95% confidence interval for the mean age an American first drinks alcohol is…

A: Lower limit = 16 - 1.2 =14.8 Lower limit = 16 + 1.2 =17.2

Q: igh school soccer league there are a total of 256 players.

A: Given that Total players in high school soccer league (n) = 256 players The mean height of the…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: In a survey of 3235 adults 1499 say they have started paying bills online in the last year. A 99%…

A: Solution: Let X be the number of adults say they have started paying bills online in the last year…

Q: andom sample of 1200 high school freshmen was taken and it was found that 559 of them were reading…

A: The population proportion (p) will be proportion of high school freshman who reads at or above their…

Q: A survey of 20 people asked, “If you’ve ever been married, how old were you when you were first…

A:

Q: n a survey, 25 people were asked how much they spent on their child's last birthday gift. The…

A: Givensample size(n)=25Mean(x)=38standard deviation(s)=19confidence interval(c)=98%

Q: It is believed that slightly over 50% of Americans own pets. A 95% confidence interval for the…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: A surprising number of young adults (ages 19 to 25) still live in their parents' homes. A random…

A:

Q: 7 out of 70 students said they were comfortable with “working in a workplace with a lot of…

A: Given that  57 out of 70 students said they were comfortable with “working in a workplace with a lot…

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: A medical study showed that 57 of 300 persons failed to recover from a given disease. Find a 95%…

A: Sample size: Number of successes: Confidence level:

Q: Insurance companies are interested in knowing the population percent of drivers who always buckle up…

A: Givenx=316sample size(n)=391Confidence level=95%p^=xn=316391≅0.8082

Q: A popular weight loss program claims users will lose weight each month. Linda samples 25 dieters and…

A: We have given that,  Sample mean (x̄) = 10 pounds, standard deviation (s) = 2 pounds and sample size…

Q: In a survey of 2646 ​adults, 1401 say they have started paying bills online in the last year.…

A: Number of adults (n)  = 2646 Number of adults who say they have started paying bills online in the…