Water pressure increases as depth increases. At the surface of a swimming pool, where pressure is 101325 Pa, a spherical beach ball has a radius of 0.3 m. Suppose the ball is pushed under water to a depth where the pressure is 140525 Pa. Calculate the change in volume of the beach ball at that depth? The ball is filled with air. You may need the following information: Density of air: 1.225 kg/m³ Density of water: 1000 kg/m3 Bulk modulus of air: 1.4 x 105 N/m² Bulk modulus of water: 2.1 × 10° N /m²

College Physics
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Author:Paul Peter Urone, Roger Hinrichs
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Chapter11: Fluid Statics
Section: Chapter Questions
Problem 43PE: In an immersion measurement of a woman's density, she is found to have a mass of 62.0 kg in air and...
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Water pressure increases as depth increases. At the surface ofa swimming pool, where pressure
is 101325 Pa, a spherical beach ball has a radius of 0.3 m. Suppose the ball is pushed under
water to a depth where the pressure is 140525 Pa. Calculate the change in volume of the beach
ball at that depth? The ball is filled with air. You may need the following information:
Density of air: 1.225 kg/m³
Density of water: 1000 kg/m³
Bulk modulus of air: 1.4 × 105 N/m²
Bulk modulus of water: 2.1 × 10° N /m²
Transcribed Image Text:Water pressure increases as depth increases. At the surface ofa swimming pool, where pressure is 101325 Pa, a spherical beach ball has a radius of 0.3 m. Suppose the ball is pushed under water to a depth where the pressure is 140525 Pa. Calculate the change in volume of the beach ball at that depth? The ball is filled with air. You may need the following information: Density of air: 1.225 kg/m³ Density of water: 1000 kg/m³ Bulk modulus of air: 1.4 × 105 N/m² Bulk modulus of water: 2.1 × 10° N /m²
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