Crater Lake in Oregon is the deepest lake in the United States, with a maximum depth of 655 m. The density of freshwater is 1.00 ✕ 103 kg/m3. (a) If the air pressure above the lake, which has a surface altitude of 1800 m, is 8.00 ✕ 104 Pa, what is the absolute pressure at the bottom of the lake? (b) What is the force of the lake's water on each window of a submarine near the lake bottom if each of its circular windows has an area of 118 cm2? (Enter the magnitude.)

(a) Calculate the absolute pressure at an ocean depth of 85 m. Assume the density of sea water is 1 021 kg/m3 and the air above exerts a pressure of 101.3 kPa. (b) At this depth, what is the buoyant force on a spherical submarine having a diameter of 5.30 m?

An otter is swimming in the deep area of his tank at the zoo. The surface area of the otter's back is A = 0.45 m², and you may assume that his back is essentially flat. The gauge pressure of the water at the depth of the otter is P = 10500 Pa. Po- F= α 8 g k Po Enter an expression for the magnitude of the force F on the back of the otter in terms of the gauge pressure P and the atmospheric pressure ß A h m S π d j P t Solve for the magnitude of the force F, in newtons. The direction of the force F is always (||7|8 | 9 1^^ 4 5 6 1 2 3 0 END NO BACKSPACE DEL CLEAR * y HOME X Ⓒtheexpertta.com to the surface the water is in contact with (in this case, the back of the otter).

The bottom of a rectangular swimming pool is 15 m × 25 m. If the atmospheric pressure above the swimming pool changes from 738 to 768 mm of mercury, determine the amount by which the force on the bottom of the pool increases? (Assume the density of mercury is 13.6 ✕ 103 kg/m3.)

A submersible vehicle is in a lake at a depth of 29.6 m. What is the absolute pressure (in Pa) at this depth? The density of the water in the lake is 1.00 ✕ 103 kg/m3, and the air above is at a pressure of 101.3 kPa. Pa (b) The submersible vehicle has a circular window with a diameter of 42.0 cm. What force (in N) is exerted by the water on the window of the vehicle at the depth from part (a)? (Enter the magnitude.)       a) Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 26.6 m. Assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kPa. Pa (b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 29.0 cm?         Mercury is poured into a U-tube as shown in Figure a. The left arm of the tube has cross-sectional area A1 of 10.8 cm2, and the right arm has a cross-sectional area A2 of 5.50 cm2. One hundred grams of water…

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2290 Pa greater than atmospheric pressure? The density of glycerine is 1.26x103 kg/m3.

A submarine is stranded on the bottom of the ocean with its hatch 25 m below the surface. In this problem, assume the density of sea water is 1.03 × 103 kg/m3. Calculate the force, in newtons, needed to open the hatch from the inside, given it is circular and 0.55 m in diameter. The air pressure inside the submarine is 1.00 atm.

A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2210 Pa greater than atmospheric pressure? The density of glycerine is 1.26 × 10° kg/m³. h =

(a) Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 32.6 m. Assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kPa.(b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 33.0 cm?

Calculate the absolute pressure at the bottom of a fresh-water lake at a depth of 31.6 m. Assume the density of the water is 1.00 ✕ 103 kg/m3 and the air above is at a pressure of 101.3 kPa. (b) What force is exerted by the water on the window of an underwater vehicle at this depth if the window is circular and has a diameter of 32.0 cm?