Water Oil (sg 0.90) 125 mm 475 mm 250 mm 50 mm Mercury (sg = 13.54) FIGURE 3.31 Problem 3.67. 3.67 For the compound manometer shown in Fig. 3.31, calcu- late the pressure at point A. 3,68 For the 3. 60

Q.1 (50%): Determine the pressure difference between points A and B in Fig. below. Kerosene rd.-0.82 -Air r.d. 0.0118 Trocm Benzene 21cm 90 cm 15 cm r.d=0.88- 'Water Mercury r.d.=13.6

6 PLEASE PROVIDE COMPLETE SOLUTION

For the following inverted manometer setup, if the pressure at x is 200 kPa, what is the pressure at y? Oil(SG 0.90) 60 in. Px 10 in. Water Py 20 in.

نقطة واحدة * :Q 5 Q: The tank in Figure is closed at top and contains air at pressure PA. Calculate the value of PA of manometer readings shown. Air Open tube Oil(S.G-0.7 150 cm 200 cm Wat 10 cm Mercury

a pipe has a pressure of 4000 pascal and is connected to a 36 degree inclined single column manometer. the level of mercury in the reservoir is at a height 20 cm below the center of the pipe. The length of the inclined column which is at the same level from the mercury inside the reservoir up to the end of the column at the reight limb is 25 cm. Find the specific gravity of the fluid inside the pipe. The area of the reservoir is 125 times the area of the right limb of the manometer

a)Determine the depth z (in feet) of oil in the tank.b)Determine the differential reading, h (in feet), on the manometer.

use meter for unit

Please solve

Convert the 115/85 systolic/diastolic pressures given in millimeters of Hg to Pa .