**Water Pumping System from Lake to Ranger Station**Water is to be pumped from a lake to a ranger station on the side of a mountain. The length of pipe immersed in the lake is negligible compared to the length from the lake surface to the discharge point. The flow rate is to be 95.0 gallons per minute, and the flow channel is a standard 1-inch Schedule 40 steel pipe (ID = 1.049 inch). A pump capable of delivering 8 horsepower is available.**Friction Loss:**\[\hat{F} \, \left(\text{ft} \cdot \text{lbf}_{f} / \text{lb}_{m}\right) = 0.0410 L,\]where \( L \) (feet) is the length of the pipe.**Diagram Explanation:**The diagram shows a simplified side view of the pumping system. The main components include:- **Lake:** The water source from which water is being pumped.- **Pipe:** A straight, inclined pipe represented by a black line. It transports water from the lake to the ranger station.- **Pump:** Illustrated as a circular device, it boosts water flow through the pipe.- **Incline Angle (\( \alpha^\circ \)):** The angle of the pipe relative to the horizontal ground.- **Length (L):** The full length of the pipe from the lake surface to the discharge point at the ranger station.- **Height (z):** The vertical distance between the lake surface and the discharge point.This setup illustrates the basic principles of fluid dynamics and hydraulic engineering used in designing efficient water transport systems on inclined terrains. Suppose the pipe inlet is immersed to a significantly greater depth below the surface of the lake, but it discharges at the elevation calculated in the previous part of the problem. The pressure at the pipe inlet would be greater than it was at the original immersion depth, which means that ΔP from inlet to outlet would be greater, which in turn suggests that more water could be pumped with the same power. In fact, however, less water can be pumped.Calculate the percentage decrease in flow rate caused by immersing the pipe inlet to a depth of 180 ft at the same angle (α = 40°).

Given that, Flow rate of water, q=95 gal/minq=0.0066 m3/sec=0.2339 ft3/sec,Inner diameter of pipe,…

Water is to be pumped from a lake to a ranger station on the side of a mountain (see figure). The length of pipe immersed in the lake is negligible compared to the length from the lake surface to the discharge point. The flow rate is to be 95.0 gal/min, and the flow channel is a standard 1-inch. Schedule 40 steel pipe (ID = 1.049 inch). A pump capable of delivering 8 hp (= Ws ) is available. The friction loss F (ft-lbf /lbm) equals 0.0410 L, where L (ft) is the length of the pipe.

Water is to be pumped from a lake to a ranger station on the side of a mountain (see figure). The length of pipe immersed in the lake is negligible compared to the length from the lake surface to the discharge point. The flow rate is to be 95.0 gal/min, and the flow channel is a standard 1-inch. Schedule 40 steel pipe (ID = 1.049 inch). A pump capable of delivering 8 hp (= Ws ) is available. The friction loss F (ft-lbf /lbm) equals 0.0410 L, where L (ft) is the length of the pipe.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

Handwriting not allow please
It's just two step problem ,Please solve Correctly.
Given, Point A - Inlet of a water pipe Pressure at the inlet of a water tap = 300kPa Water Pipe internal dimension is = 30mm Water Temp = 20 degrees Point B - section of pipe Pressure = unknown Open to atmosphere. elevation drop of 20m from point A to Point B Assume frictionless piping system. Assume turbulent flow. What is the pressure and flow rate at point B?
hydraulics
What is Total Head of submersible pump has Q=287 l/sec D=0.8 m Lenght of pipe=12000 m Fluid=water Fittings=6 elbows 45 degree Material=GRP Depth of well=9 meter Please take your time
What is the hydraulic radius of a circular pipe that is half full with water?
None
For a 6.25-inch Model 4075 pump operated at 1160 rpm, if 450 GPM of water is to be delivered, what will be the estimated pump head in ft? HEAD IN FEET 30 25 0 0 0 10 O 6 ft 7.25" (184mm) 20 7.00" (178mm). 6.75" (171mm). 6.50" (165mm)] 15 6.25" (159mm). 5 O 16 ft O 20 ft O 12 ft aco® L/SEC 5 OT 10 Model 4075 FI & CI Series 15 -6-6 ⁰ dº 20 ANA 888 778 25 REQUIRED NPSH do 1160 RPM November 1, 2010 K ・dº- [M 90 do 30 8800 81 1HP(.75KW) DeJ kin do 60% 35 do 50 Curve no. 2175 Min. Imp. Dia. 6.25" Size 5 x 4 x 7.0 40 45 3HP(2.2KW), 2HP(1 5KW) 5HP(1 1KW)> CURVES BASED ON CLEAR WATER WITH SPECIFIC GRAVITY OF 1.0 L 75 150 225 300 375 450 525 600 675 FLOW IN GALLONS PER MINUTE NOWONG FEET 15 12 7 6 2 1 NPSH 758 50 5 HEAD IN METERS 45 586888 KPO 60 40 20 10 LO HEAD IN KILOPASCALS
Power for Pumping in a Flow System. Water is being pumped from an open water reservoir at the rate of 2.0 kg/s at 10°C to an open storage tank 1500 m away. The pipe used is Schedule 40 3 1\2 -in. pipe and the frictional losses in the system are 625 J/kg. The surface of the water reservoir is 20 m above the level of the storage tank. The pump has an efficiency of 75%. a. What is the kW power required for the pump ? b. If the pump is not present in the system, will there be a flow?
Part A plz
show all steps and working please.
Please answer in clear handwriting.