voo ell ell The phase voltage of the generator. Ep = The phase voltage of the load. Vp = The line current. LL= The phase current of the load. p= ECA-2082120° units untis untis EAB=20820* units 2092 2092 EBC-2082-120° 2092 b

The single-line diagram of a three-phase power system is shown below. Bus 2 Q+01 10+Q T₁ T₂ Y Bus 1 Device Generator G₁: Generator G₂: Transformer T1: Transformer T2: Transformer T3: Line 2 Line 1 toot Load T3 S₁ 48 MVA 25 MVA 50 MVA 30 MVA 50 MVA Line 3 Bus 3 Figure 1 The manufacturer's nominal ratings are given as follows: Bus 4 (L-L)n 20 kV 13.8 kV 20/110 kV 13.8/110 kV 11/110 kV X₁ 20% 15% 8% 6% 10% (Note: Of course, the Xn in each row is the per-unit value impedance of that equipment when using on the Sn (Capacity of that equipment) and the U(L-L)n (Line-to-line voltage of that equipment) of that row as the MVA base and the voltage base.) The balanced three-phase load at bus 4 absorbs 60 MVA at 0.75 power factor (lagging), and lines 1, 2, and 3 have the reactance of 400, 32 Q, and 300, respectively. (a) Using the common base Sb = 50 MVA, draw the impedance diagram in per unit including the load impedance. (b) Now there is a solid balanced three-phase short-circuit fault at Bus 4,…

Glasses For the shown Crank diagram, if the voltage at the load is equal to ER=35 Volt and the characteristic impedance Z0-50 Ohm, then the Current scale for this diagram is equal exactly to 3A/8 d3 d=0=x/2 do 7.68 13.14 C. 10 4. 13.11 7.71 d2 1/4 1/8 35.5 mA/cm 53.3 mA/cm 90.8 mA/cm O 50 mA/cm 19

A three-phase, Y-connected, synchronous generator supplies a rated load of 12 MW at a power factor of 0.8 lagging. The synchronous impedance is 0.2 + j2 2/phase. If the terminal (line) voltage is 11 kV, calculate the no load line voltage. What is the voltage regulation? Vline (no load)=Eline=13 kV VR(%) 18.19%

Draw the reactance diagram for the following power system. Consider a base of 13.8 KV and 44 MVA in the circuit of generator 1.G 1 : 20 MVA, 13.8 KV, X // = 20%G 2 : 30 MVA, 18 KV, X // = 20%G 3 : 30 MVA, 20 KV, X // = 20%T 1: 25 MVA, 220Y/13.8Δ KV, x = 10%T 2: 30 MVA, 220Y/18Δ KV, x = 10%Reactance of the transmission line = j 0.8 p.u on a base of 220 KV and 30 MVA