Voltage Distribution Channel with netral-phase, with voltage 22 kV and internal impedance is 2+j3, connected with 10 unit of electric motor with specification 10KVA, power factor 0,85 Impedance 5+J4. Find the reactor to make the load distribution to maximum.

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Voltage Distribution Channel with netral-phase, with voltage 22 kV and internal impedance is 2+j3, connected with 10 unit of electric motor with
specification 10KVA, power factor 0,85 Impedance 5+J4. Find the reactor to make the load distribution to maximum.
Transcribed Image Text:Voltage Distribution Channel with netral-phase, with voltage 22 kV and internal impedance is 2+j3, connected with 10 unit of electric motor with specification 10KVA, power factor 0,85 Impedance 5+J4. Find the reactor to make the load distribution to maximum.
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Electrical Engineering homework question answer, step 1, image 1

motor 10 unit = 10 kWh

10kVA and 0.85 power factor

Z = 5 +j4

Active power load

=10×103 Cos=10×103×0.85=8.5kW

 

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