Q 4/ A 3000 kVA, 3-phase, star-connected, 50 Hz, 2800 V alternator has resistance 0.120. A field current of 60 A produces a short circuit equal to full load current of 618 A in each line. The same field current produces an emf of 800 V on open circuit. Determine : 1_Synchronous Impedance. . 2_Synchronous Reactance.. . 3_Phase Current.. .Amp 4_The excitation voltage of the machine ...V. at 0.8 power factor lagging * 5_The full load regulation at 0.8 power factor lagging. e 9:12 älues

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Q 4/
A 3000 kVA, 3-phase, star-connected,
50 Hz, 2800 V alternator has
resistance 0.120. A field current of 60
A produces a short circuit equal to full
load current of 618 A in each line. The
same field current produces an emf
of 800 V on open circuit. Determine :
1_Synchronous Impedance ..
2_Synchronous Reactance.. .
3_Phase Current. .Amp
4_The excitation voltage of the
machine ...V. at 0.8 power factor
lagging *
5_The full load regulation at 0.8
power factor lagging.
معدلة 9:12 ص
Transcribed Image Text:Q 4/ A 3000 kVA, 3-phase, star-connected, 50 Hz, 2800 V alternator has resistance 0.120. A field current of 60 A produces a short circuit equal to full load current of 618 A in each line. The same field current produces an emf of 800 V on open circuit. Determine : 1_Synchronous Impedance .. 2_Synchronous Reactance.. . 3_Phase Current. .Amp 4_The excitation voltage of the machine ...V. at 0.8 power factor lagging * 5_The full load regulation at 0.8 power factor lagging. معدلة 9:12 ص
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