vly Questions bartleby .masteringphysics.com/myct/itemView?assignmentProblemlD=134309602&offset3Dnext Apps (1) ইমাম মাহদী কবে... YouTube to MP3 Co.. phone cover for mo... AGARWAL-PHY-166 W3 n 8 Part A If the coefficient of kinetic friction between a 27 kg crate and the floor is 0.38, what horizontal force is required to move the crate at a steady speed across the floor? Express your answer to two significant figures and include the appropriate units. Value Units Submit Request Answer Part B What horizontal force is required if u is zero? Hk Express your answer to two significant figures and include the appropriate units. MA Type here to search %3D

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Step by step work starting with the formula.   Q1. Calculate the centrifugal force acting on a parcel of air of mass 10.0 kg having a radius of 200 cm moving at a velocity of 5.0 m/sec2. Centrifugal acceleration is v2 divided by r, F = m x a , where v is the wind speed and r is the radius of curvature.     Q2. How much pressure is exerted on a tree by a wind blowing at velocity v = 90.0 m/sec? The mean density of air at sea level is 1.225 kg/m3. Hint: Rate of change of momentum = Applied force; mass x velocity = Force.

he FBD of the block should have looked like this.       1.    A contestant in a winter sporting event pushes a block of ice  of mass m across a frozen lake as shown in the figure. The coefficient of static friction between the block and ice is μs, and the coefficient of kinetic friction is μk. θ is the angle the force makes with the x-axis. In this part, we are going to set-up Newton's second Law equations for the cases(1) when the ice block just starts moving, and(2) when it is accelerating to the right with an acceleration a. All answers are symbolic. ALL ANSWERS ARE CASE-SENSITIVE.         Subpart 1: Newton's Second Law along the y-axis  (i) Write Newton's Second Law along the y-axis by adding all forces in the y-direction taking into account their signs (forces pointing upwards are positive and downward are negative) in terms of the normal force N, weight mg, F and θ. In both scenarios, there is no acceleration along the y-direction, therefore, ay=0.…