MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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- You are given the smaple mean and the population m standard deviation. Use this info to construct the 90% and 95% confidence intervals for the population mean. Interpert the results and compare the widths of the confidence intervals. A random sample of 50 home theater systems has a mean price of $145. Assume the population standard deviation is $17.30arrow_forwardYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 45 home theater systems has a mean price of $142.00. Assume the population standard deviation is $18.80. Construct a 90% confidence interval for the population mean. The 90% confidence interval is (____, ____) (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is (____, ____) (Round to two decimal places as needed.)arrow_forwardTina catches a 14-pound bass. She does not know the population mean or standard deviation. So she takes a sample of five friends and they say the last bass they caught was 9, 12, 13, 10, and 10 pounds. Find the t and calculate a 95% (α = .05) confidence interval.arrow_forward
- If [0.64, 0.82] is a confidence interval for the population proportion. Find the value of the point estimator of the population proportion. Select one: O a. 0.73 O b. 0.70 O c. 0.74 O d. 0.72arrow_forwardNeed to solve for 95% interval and 90% intervalarrow_forwardAccording to a Pew Research Center nationwide telephone survey of adults conducted March 15 to April 24, 2011, 69% of college graduates said that their college education gave them maturity (Time, May 30, 2011). Suppose that this survey included n = 1415 college graduates. a. What is the point estimate of the corresponding population proportion? i b. Construct a 99% confidence interval for the proportion of all college graduates who will say that their college education gave them maturity. What is the margin of error for this estimate? Round your answers to three decimal places. The confidence interval is i toarrow_forward
- Determine whether the statement below makes sense or does not make sense. Explain clearly. Based on our sample, the 95% confidence interval for the mean amount of television watched by adults in a nation is 3.5 to 4.1 hours per day. Therefore, there is 95% chance that the mean for all adults in the nation will fall somewhere in this range and a 5% chance that it will not. Choose the correct answer below. O A. The statement makes sense. There is 95% probability that the confidence interval limits actually contain the true value of the population mean, so the probability it does not fall in this range is 100% - 95% = 5%. O B. The statement does not make sense. The probability the population mean is greater than the upper limit is 5% and the probability it is less than the lower limit is 5%, so the probability it does not is 5% + 5% = 10%. O C. The statement makes sense. There is 5% probability that the confidence interval limits do not contain the true value of the sample mean, so the…arrow_forwardSuppose we wish to study the average income of Cactus Club customers, so we plan to conduct a research project with a 95% confidence level. We need our range of error (E) to be no greater than $500. Based on our past experience, we estimate the sample standard deviation to be $5,000. What sample size do you need in order to conduct the research? Select one: a. 372 b. 784 c. 824 d. 385 e. 196arrow_forwardUse the given data to construct a confidence interval for the population proportion p of the requested level. x = 52, n = 71, confidence level 95% Round the answer to at least three decimal places. D. The confidence interval isarrow_forward
- You are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 60 home theater systems has a mean of $147.00. Assume the population standard deviation is $19.10 Construct a 90% confidence interval for the population mean. The 90% confidence interval is Construct a 95% confidence interval for the population mean The 95% confidence interval isarrow_forwardneed help!arrow_forwardYou are given the sample mean and the population standard deviation. Use this information to construct the 90% and 95% confidence intervals for the population mean. Interpret the results and compare the widths of the confidence intervals. If convenient, use technology to construct the confidence intervals. A random sample of 40 home theater systems has a mean price of $130.00. Assume the population standard deviation is $18.50. The 90% confidence interval is ( 125.19), 134.81). (Round to two decimal places as needed.) Construct a 95% confidence interval for the population mean. The 95% confidence interval is ( 124.27 , 135.73). (Round to two decimal places as needed.) Interpret the results. Choose the correct answer below. O A. With 90% confidence, it can be said that the population mean price lies in the first interval. With 95% confidence, it can be said that the population mean price lies in the second interval. The 95% confidence interval is narrower than the 90%. O B. With 90%…arrow_forward
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