Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question

Given the following circuit:

RT = 10Ω --> Is = 20V / 10Ω --> Is = 2A --> Is = IR1 = 2A

Since I1 = I2 +  I3, therefore, when the circuit flows to the end, I2 + I3 = I1 once more, making IR2 to have the same current as IR1, therefore IR2 = 2A

I3 = Is *  (R3 / (R3 + R4 + R5)) --> 2A * (6Ω / (6Ω + 1Ω + 2Ω)) --> 2A * (6/9)  --> I3 = 4/3A  --> IR3 = 2/3A

I3 = IR4 = 4/3A

I3 = IR5 = 4/3A

Can you check if its correct?

V1
=20V
R1
w
50
R2
w
30
w
R3
60
R4
м
10
R5
20
expand button
Transcribed Image Text:V1 =20V R1 w 50 R2 w 30 w R3 60 R4 м 10 R5 20
I₁
Ri
www
5
RY
15
↓
R5
R3
22
V₁
I2 26л
3
20V
R2
АМ
ЗЛ
I₁ = 12 + 13
expand button
Transcribed Image Text:I₁ Ri www 5 RY 15 ↓ R5 R3 22 V₁ I2 26л 3 20V R2 АМ ЗЛ I₁ = 12 + 13
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