Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN: 9780133923605
Author: Robert L. Boylestad
Publisher: PEARSON
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Question
Given the following circuit:
RT = 10Ω --> Is = 20V / 10Ω --> Is = 2A --> Is = IR1 = 2A
Since I1 = I2 + I3, therefore, when the circuit flows to the end, I2 + I3 = I1 once more, making IR2 to have the same current as IR1, therefore IR2 = 2A
I3 = Is * (R3 / (R3 + R4 + R5)) --> 2A * (6Ω / (6Ω + 1Ω + 2Ω)) --> 2A * (6/9) --> I3 = 4/3A --> IR3 = 2/3A
I3 = IR4 = 4/3A
I3 = IR5 = 4/3A
Can you check if its correct?
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