V. vi. Oxygen undergoes an adiabatic, reversible compression process from 300 K and 300 kPa to 960 kPa. What is the temperature, in K, of the O2 in the final state? Report your answer to one decimal place. 2 kg of air is expanded isentropically from 500 K at 0.2 m³ to 400 K. What is the final specific volume of the air, in m³/kg? Report your answer to 4 significant figures.

V. vi. Oxygen undergoes an adiabatic, reversible compression process from 300 K and 300 kPa to 960 kPa. What is the temperature, in K, of the O2 in the final state? Report your answer to one decimal place. 2 kg of air is expanded isentropically from 500 K at 0.2 m³ to 400 K. What is the final specific volume of the air, in m³/kg? Report your answer to 4 significant figures.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

QUESTION 3 Water vapor enters a valve at 0.7 bar, 360°C and exits at 0.35 bar. If the water vapor undergoes a throttling process (means constant enthalpy & reduce pressure significantly), determine the rate of entropy production within the valve, in kJ/K per kg of water vapor flowing. TTTT Paragraph v 3 (12pt) -三, T Arial Of Mashups - HTML CSS ick Save and Submit to saue and sSuhmit Click Sque All Anguamc to caua ll !!!
One-quarter Ibmol of oxygen gas (O2) undergoes a process from p1 = 20 Ib/in?, T1 = 500°R to p2 = 150 lb;/in?. For the process W = -500 Btu and Q = -127.5 Btu. Assume the oxygen behaves as an ideal gas. Determine T2, in °R, and the change in entropy, in Btu/°R. Step 1 Determine T2, in °R. T2 = °R Save for Later Attempts: 0 of 1 used Submit Answer Step 2 The parts of this question must be completed in order. This part will be available when you complete the part above.
a. Specific volume of superheated steam at 10kPa and 150°cb. Internal energy of superheated steam at 20kPa and 110°Cc. Entropy of superheated steam at 101.325kPa and 200°Cd. Enthalpy of saturated liquid water 298.15 Ke. Enthalpy of evaporation of water at 220°C and 2319.8 kPa
DESCRIBE THE ENTROPY CHANGE OF PURE SUBSTANCES?
Can you answer this one my thermodynamics question problem.... Consider 1kg of water that is heated at constant pressure (0.50 MPa) from a wet state (x1 = 85%) to 400°C. Locate the end state points on the Mollier chart and determine (a) the change of enthalpy and (b) the change of entropy. Ans. (a) 739 kJ/kg, (b) 1.70 kJ/kg
QUESTION 4 What is the volume and enthalphy of 2kg of steam at 100 kPa and 200°C? O a. 2.1724m3 and 2875.5 kJ O b.4.3448 m3/kg and 5751 kJ/kg OC. 2.1724 m3/kg and 2875.5 kJ/kg O d.4.3448 m3 and 5751 kJ O e. none of the above
A mixture (i.e., thermodynamic system) of 0.182 kg of helium (He) and 0.091 kg ofoxygen (O2) is compressed polytropically (PVn = const.) in a piston-cylinder devicefrom 101.352 kPa and 15.56C to 413.69 kPa according to n = 1.4. Determine for theprocess: (a) the final temperature, (b) the work done, and (c) the heat energy.Clearly mention whether the work is done on or by the mixture, and whether the heatis supplied to or rejected by the mixture to the surroundings.Take the specific heat capacity at constant volume, cv for He = 3.119 kJ/(kg·K) andfor O2 = 0.659 kJ/(kg·K), and the value of gas constant R for He = 2.0769 kJ/(kg·K)and for O2 = 0.2598 kJ/(kg·K).Draw the schematic of piston-cylinder device and display the process on a hypothetical indicator diagram for the process.
2. Using the steam tables, determine the specific enthalpy, specific volume and specific enthalpy for steam at 2800 KPa and at a temperature of 300 C. a. The steam in question 2 above is taken through a process that makes it expand isentropically to a pressure of 1650 KPa. What is the final temperature, specific enthalpy, specific volume and specific entropy of the steam in this new state? b. What is the change in specific enthalpy, specific volume, temperature and specific entropy?
A mixture (i.e., thermodynamic system) of 0.182 kg of helium (He) and 0.091 kg of oxygen (O2) is compressed polytropically (PV" = const.) in a piston-cylinder device from 101.352 kPa and 15.56°C to 413.69 kPa according ton=1.4. Determine for the process: (a) the final temperature, (b) the work done, and (c) the heat energy. Clearly mention whether the work is done on or by the mixture, and whether the heat is supplied to or rejected by the mixture to the surroundings.
Q NO1: A mixture (i.e., thermodynamic system) of 0.182 kg of helium (He) and 0.091 kg ofoxygen (O2) is compressed polytropically (PVn = const.) in a piston-cylinder devicefrom 101.352 kPa and 15.56C to 413.69 kPa according to n = 1.4. Determine for theprocess: (a) the final temperature, (b) the work done, and (c) the heat energy.Clearly mention whether the work is done on or by the mixture, and whether the heatis supplied to or rejected by the mixture to the surroundings.Take the specific heat capacity at constant volume, cv for He = 3.119 kJ/(kg·K) andfor O2 = 0.659 kJ/(kg·K), and the value of gas constant R for He = 2.0769 kJ/(kg·K)and for O2 = 0.2598 kJ/(kg·K).Draw the schematic of piston-cylinder device and display the process on a hypothetical indicator diagram for the process.
Entropy of the mixture?
A 25 kg copper block at 373 K is dropped into an insulated tank that contains 80 L of water at 293 K. Assume that the specific heat of steel is 0.72 kJ/kg-K and that of oil is 2.4 kJ/kg.K. 1. Determine the final equilibrium temperature. Answer in kJ/K 2. Calculate the total change in entropy. Answer in kJ/K 3. Compute the amount of work lost in the process. Answer in kJ/K